If h(x) = squareroot 3 + 2f'(x), where f(5) = 3 and f '(5) = 2, find h'(5).
1 answer:
Answer:
h'(5) = ⅔
Step-by-step explanation:
I assume you mean h(x) = √(3 + 2f(x)).
Taking derivative using chain rule:
h'(x) = ½ (3 + 2f(x))^-½ · 2f'(x)
h'(x) = f'(x) / √(3 + 2f(x))
h'(5) = f'(5) / √(3 + 2f(5))
h'(5) = 2 / √(3 + 2 · 3)
h'(5) = ⅔
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