A tangent line is located outside the circle so the answer would be AB
Answer:
f-1(x) = (x - 16)/40
B
Step-by-step explanation:
Call f(x) = y
Interchange x and y
x = (5y + 2)*8 Remove the brackets
x = 40y + 16 Subtract 16 from both sides
x - 16 = 40y Interchange the left and right sides
40y = x - 16 Divide by 40
y = (x - 16)/40
f-1(x) = (x - 16)/40
Answer:
120
Step-by-step explanation:
75-15=60. (Edit) Just realized that she spent her allowance that week, so it would be 120 because you need to multiply.
Answer:
The required result is proved with the help of angle bisector theorem.
Step-by-step explanation:
Given △ABD and △CBD, AE and CE are the angle bisectors. we have to prove that
Angle bisector theorem states that an angle bisector of an angle of a Δ divides the opposite side in two segments that are proportional to the other two sides of triangle.
In ΔADB, AE is the angle bisector
∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment AD to the line segment AB.
→ (1)
In ΔDCB, CE is the angle bisector
∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment CD to the line segment CB.
→ (2)
From equation (1) and (2), we get
Hence Proved.