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guajiro [1.7K]
3 years ago
15

If a residence is rented for 15 days or more and is used for personal purposes for not more than 14 days or 10 percent of the da

ys rented, whichever is greater, no allocation of expenses is required and the taxpayer may claim a deduction for the full amount of the expenses.
Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
7 0

Answer:

False.

Step-by-step explanation:

For a residence whose primary usage is for rental purpose, its expenses must still be allocated between personal and rental days as agreed between the client and the owner

All terms of agreement remains valid and there's no other allocation of expenses that will be required. The taxpayer cannot claim any deduction for the full amount of the expenses.

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A realtor would like to create a 95% confidence interval for the average price of a house in Franklin County, Ohio. To accomplis
VMariaS [17]

Answer:

320128-1.96\frac{50324}{\sqrt{529}}=315839.52    

320128+1.96\frac{50324}{\sqrt{529}}=324416.48    

So on this case the 95% confidence interval would be given by (315839.52;324416.48)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=320128 represent the sample mean

\mu population mean (variable of interest)

\sigma=50324 represent the population standard deviation

n=529 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

320128-1.96\frac{50324}{\sqrt{529}}=315839.52    

320128+1.96\frac{50324}{\sqrt{529}}=324416.48    

So on this case the 95% confidence interval would be given by (315839.52;324416.48)    

8 0
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Answer:

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Answer:

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Step-by-step explanation:

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