The quantity of electricity : 2 Faraday = 193000 Coulomb
<h3>Further explanation</h3>
Given
2 moles of electrons
Required
The quantity of electricity
Solution
According to Faraday, the amount of current flowing in the electrolysis cell is closely related to the amount of substance that reacts
1 Faraday is the amount of electricity that is passed in the electrolysis cell to obtain 1 mole of electrons. 1 mole of electrons is equivalent to an electric charge of 96500 Coulombs.
The conversion / relationship can be stated as follows:
1 Faraday = 1 mole of electrons = 96500 Coulombs
1 faraday = coulomb / 96500
Can be formulated
Coulomb = Q = I. t so:
so for 2 moles electrons :
= 2 x 96500 C
= 193000 C
= 2 Faraday
The type of compound is formed between coach and a carboxylic acid alcohol + carboxylic acid → ester + water.
How carboxylic acids are formed?
A acid is produced after the acidic hydrolysis of esters and carboxylates are produced after the basic hydrolysis of an ester.
What are the functional group of alcohol and carboxylic acid?
Alcohols contain the hydroxyl functional group and may be primary, secondary, or tertiary. Ethers are compounds with an oxygen atom bonded to 2 alkyl groups. Aldehydes and ketones contain the carbonyl functional group
Can a compound be a acid and an alcohol?
Esters are represented by the formula RCOOR', where R and R' are hydrocarbon groups. The ester, which is compound derived from a carboxylic acid and an alcohol in which the OH of the acid is replaced by an OR group, looks somewhat sort of a n ether and also somewhat like a carboxylic acid.
Learn more about carboxylic acid :
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The force acting between two charged particles A and B is 5.2 x 105 newtons. Charges A and B are 2.4 x 102 meters apart. If the charge on particle A is 7.2 x 108 coulombs, what is the charge of particle B? (k 7 9.0 x 109 newton meters?/coulomb)
1) Chemical reaction: HCN + H₂O → CN⁻ + H₃O⁺.
c(HCN) = 2,2 M = 2,2 mol/L.
pKa(HCN) = 9,21.
Ka = 6,16·10⁻¹⁰.
[CN⁻] = [H₃O⁺] = x.
[HCN<span>] = 2,2 M - x.
</span>Ka = [CN⁻] · [H₃O⁺] / [HCN].
6,16·10⁻¹⁰ = x² / 2,2 M -x.
Solve quadratic equation: [CN⁻] = [H₃O⁺] = 0,0000346 M.
[HCN] = 2,2 M - 0,0000346 M = 2,199 M.
2) pH = - log[H₃O⁺].
pH = -log( 0,0000346 M).
pH = 4,46.
Hydrocyanic acid and hydronium ion (H₃O⁺) are acids. Cyanide anion (CN⁻) is the strongest base in the system, cyanide anion accept protons in chemical reaction.
pKb = pKw - pKa.
pKb = 14 - 9,21 = 4,79.
