Question

if a quadratic equation with real coefficients has a discriminant of -36 then what type of roots does it have

Answer 1

Step-by-step explanation:

We have,

If a quadratic equation with real coefficients has a discriminant of -36.

The general form of quadratic equation is :

$ax^2+bx+c=0$

The discriminant of this equation is : $D=b^2-4ac$

If D=0, it will have 1 real roots

If D>0, it will have 2 real roots

If D<0, it will have no real roots

We have,

D = -36 < 0, so, the quadratic equation will have no real roots.