All categories

3 years ago

Solve for x. I need help with this problem.

Mathematics

1 answer:

Advocard [28]3 years ago

7 0

Answer:

x = 9

Step-by-step explanation:

Rule: the two interior angles F and E when added, equal <FGH.

6x + 16 + 60 = 13x + 13 Combine the terms on the left.

6x + 76 = 13x + 13 Subtract 13 from both sides.

6x + 76-13 = 13x Combine

6x + 63 = 13x Subtract 6x from both sides.

63 = 7x Divide by 7

63/7 = x

x = 9

You might be interested in

Find the area of the region enclosed by the graphs of the functions

Vaselesa [24]

Answer:

$\displaystyle A = \frac{8}{21}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Functions
Function Notation
Graphing
Solving systems of equations

Calculus

Area - Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

*Note:

Remember that for the Area of a Region, it is top function minus bottom function.

Step 1: Define

f(x) = x²

g(x) = x⁶

Bounded (Partitioned) by x-axis

Step 2: Identify Bounds of Integration

Find where the functions intersect (x-values) to determine the bounds of integration.

Simply graph the functions to see where the functions intersect (See Graph Attachment).

Interval: [-1, 1]

Lower bound: -1

Upper Bound: 1

Step 3: Find Area of Region

Integration

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^1_{-1} {[x^2 - x^6]} \, dx$
[Area] Rewrite [Integration Property - Subtraction]: $\displaystyle A = \int\limits^1_{-1} {x^2} \, dx - \int\limits^1_{-1} {x^6} \, dx$
[Area] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = \frac{x^3}{3} \bigg| \limit^1_{-1} - \frac{x^7}{7} \bigg| \limit^1_{-1}$
[Area] Evaluate [Integration Rule - FTC 1]: $\displaystyle A = \frac{2}{3} - \frac{2}{7}$
[Area] Subtract: $\displaystyle A = \frac{8}{21}$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Area Under the Curve - Area of a Region (Integration)

Book: College Calculus 10e

6 0

2 years ago

No links please. Fill in the blanks. 67ns=[?]x10^[?]s

cluponka [151]

Using scientific notation, it is found that:

67 ns = $6.7 \times 10^{-8}$ s

<h3>What is scientific notation?</h3>

A number in scientific notation is given by:

$a \times 10^b$

With the base being $a \in [1, 10)$ .

In this problem, the amount is of 67 ns.

Each ns has $10^{-9}$ seconds, hence:

$67ns = 67 \times 10^{-9}s$

We want the base between 1 and 10(exclusive), hence, we move the decimal digit one digit to the left and add one to the exponent, and the representation is:

67 ns = $6.7 \times 10^{-8}$ s

You can learn more about scientific notation at brainly.com/question/16394306

7 0

1 year ago

Simplify 2(10−x)+3(12−x)

GarryVolchara [31]

Answer:

-5x + 56

Step-by-step explanation:

Use distributive property to refine.

20 - 2x + 36 - 3x

Combine Like Terms