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mina [271]
3 years ago
6

(Y-1/4)-(y-4/5)=(y+4/10)-1

Mathematics
2 answers:
erica [24]3 years ago
7 0

Answer:

y=\frac{23}{60}

Step-by-step explanation:

(y-\frac{1}{4})-(y-\frac{4}{5})=(y+\frac{4}{10} )-1

  • First, let's deal with everything in our parentheses. This includes simplification of fractions and distributing signs.
  • Remember than when distributing, everything in the parentheses is affected by whatever is being distributed.

(y-\frac{1}{4})-(y-\frac{4}{5})=(y+\frac{4}{10} )-1\\(y-\frac{1}{4})-(y-\frac{4}{5})=(y+\frac{2}{5})-1

  • A quick note that we can get rid of the parentheses once there is only addition and subtraction left next to the parentheses.

(y-\frac{1}{4})-(y-\frac{4}{5})=(y+\frac{2}{5})-1\\y-\frac{1}{4}-y+\frac{4}{5}=y+\frac{2}{5}-1

  • Now that the parentheses are gone, we can add and subtract in any order as long as we don't break the rules of addition and subtraction.

y-\frac{1}{4}-y+\frac{4}{5}=y+\frac{2}{5}-1\\y-y-\frac{1}{4}+\frac{4}{5}=y+\frac{2}{5}-1\\-2y-\frac{1}{4}+\frac{4}{5}=y+\frac{2}{5}-1

  • Let's move all our fractions to one side, and all our unknowns to the other.

-2y-\frac{1}{4}+\frac{4}{5}=y+\frac{2}{5}-1\\-3y=\frac{1}{4}-\frac{4}{5}+\frac{2}{5}-1

  • We need a common denominator for our fractions. The quickest way to do this only two different denominators is to multiply the two denominators together. 4*5=20, so we will multiply both the numerator and the denominator by whatever we need to to get 20.

-3y=\frac{1}{4}-\frac{4}{5}+\frac{2}{5}-1\\-3y=\frac{1}{4}(\frac{5}{5})-\frac{4}{5}(\frac{4}{4})+\frac{2}{5}(\frac{4}{4})-1\\-3y=\frac{5}{20}-\frac{16}{20}+\frac{8}{20}-1

  • add the denominators together. -1=-\frac{20}{20}

-3y=\frac{5}{20}-\frac{16}{20}+\frac{8}{20}-1\\-3y=\frac{5}{20}-\frac{16}{20}+\frac{8}{20}-\frac{20}{20}\\-3y=\frac{13}{20}-\frac{36}{20}\\-3y=\frac{-23}{20}\\-\frac{1}{3}(-3y)=-\frac{1}{3}(-\frac{23}{20})\\y=\frac{23}{60}

Arte-miy333 [17]3 years ago
5 0

Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Let the Area of smaller watch face be A_1

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Also Let the radius of smaller watch face be r_1

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Since the watch face is in circular form.

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\frac{16}{25}= \frac{{r_1}^2}{{r_2}^2}

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\sqrt{\frac{16}{25}}= \sqrt{\frac{{r_1}^2}{{r_2}^2}}\\\\\frac{4}{5}= \frac{r_1}{r_2}

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Step-by-step explanation:

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