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4 years ago

The electrons lost from the reaction center of photosystem ii are replaced by the electrons from?

1 answer:

5 0

In photosystem II, light strikes on a photosynthetic pigment. Energy is absorbed, then energy bounces to the chlorophyll molecule in the reaction center, which releases two energized electrons, the electrons are replaced by two electrons stripped from a water molecule, forming oxygen gas ( $O_2$ ) and two hydrogen ions ( $H^+$ )

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You conduct an experiment in which you measure the temperature (T) and volume (V) of a mysterious sphere of gas at several diffe

____ [38]

Volume of the gas is 525 L.

Explanation:

It is given that the volume of the gas divided by the temperature is 1.75.

V/T = 1.75

As per the Charles law, volume is proportional to the temperature.

V ∝ T

V/T = constant

Now we have to find V, and T is given as 300 K.

So plugin the values as,

V/300 = 1.75

Rearranging the equation to get V as,

V = 1.75×300

= 525 L

3 0

4 years ago

When 108 g of water at a temperature of 23.9 °c is mixed with 66.9 g of water at an unknown temperature, the final temperature o

olganol [36]

Here,

Heat gain by the first sample of water + Heat lost by the second sample of water is equal to zero (0).

Now, Mass of water sample one = 108 g (given)

Mass of water sample two = 66.9 g (given)

Temperature for water sample one = $23.9^{0}C$

Let, temperature for water sample two =x

And, final temperature = $47.2^{0}C$

Now,

$mass of water sample one\times specific heat of water\times (T_{f} - T_{i}) + mass water sample two\times specific heat of water\times (T_{f} - T_{i}) = 0$

where, $T_{f}$ = final temperature

$T_{i}$ = initial temperature

Substitute all the given values in above formula:

$(108 g\times 4.184 J/g . K\times ( 47.2^{0}C- 23.9^{0}C) )+ (66.9 g \times 4.184 J/g . K\times (47.2^{0}C -x))= 0$

$(451.872 J/K \times (23.3^{0}C)) + (279.9096 J/K\times (47.2^{0}C -x)) = 0$

$(10528.6176 J/K(^{0}C)+ (13211.73312 J/K(^{0}C) -279.9096 J/K\times x)= 0$

$(23740.35072 J/K(^{0}C) -279.9096 J/K\times x)= 0$

$-279.9096 J/K\times x= -23740.35072 J/K(^{0}C)$

$x =\frac{23740.35072 J/K(^{0}C)}{279.9096 J/K}$

[tex x =84.81^{0}C [/tex]

5 0

3 years ago

Electron configuration of Zn+2

masya89 [10]

1s2 2s2 2p6 3s2 3p6 3d10

4 0

3 years ago

What determines the weather conditions an area?

Over [174]

Answer:

The five factors that determine the weather of any land area are: the amount of solar energy received because of latitude; the area's elevation or proximity to mountains; nearness to large bodies of water and relative temperatures of land and water; the number of such storm systems as cyclones, hurricanes, and ...

Explanation:

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3 years ago

Which gas law states, "at a given temperature, the amount of a particular gas in solution is directly proportional to the partia

larisa [96]

Petroleum gas . sulfate . directly pressure

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4 years ago