Answer:
Mass = 11.16 g
Explanation:
Given data:
Mass of hydrogen = 8 g
Mass of oxygen = 10 g
Mass of water produced = ?
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of hydrogen:
Number of moles = mass / molar mass
Number of moles = 8 g/ 2 g/mol
Number of moles = 4 mol
Number of moles of oxygen:
Number of moles = mass / molar mass
Number of moles = 10 g/ 32 g/mol
Number of moles = 0.31 mol
now we will compare the moles of hydrogen and oxygen with water.
O₂ : H₂O
1 : 2
0.31 : 2/1×0.31 = 0.62
H₂ : H₂O
2 : 2
4 : 4
Number of moles of water formed by oxygen are less this it will act as limiting reactant.
Mass of water:
Mass = number of moles × molar mass
Mass = 0.62 mol × 18 g/mol
Mass = 11.16 g
Answer:
5- number of electrons=11
Explanation:
in a neutral atom number of protons=number of electrons which in this case=11
Answer:
Cl₂(g) + 2 KBr(aq) ⇒ Br₂(l) + 2 KCl(aq)
Explanation:
Let's consider the unbalanced single displacement reaction between chlorine and potassium bromide.
Cl₂(g) + KBr(aq) ⇒ Br₂(l) + KCl(aq)
We will start balancing Cl atoms by multiplying KCl by 2.
Cl₂(g) + KBr(aq) ⇒ Br₂(l) + 2 KCl(aq)
Finally, to get the balanced equation, we have to multiply KBr by 2.
Cl₂(g) + 2 KBr(aq) ⇒ Br₂(l) + 2 KCl(aq)
The volume of the gas is 180.26 L, if there are 63.5 mol of an ideal gas at 9.11 atm at 42.80 °C.
Applying the ideal gas law PV= nRT
After rearranging the aforementioned expression, the volume might then be found as: V= n R T/ P.
Consequently, V= 63.5 mol, 0.0821, 315 K, and 9.11 atm equal 180.26 L.
<h3>How is the ideal gas equation defined?</h3>
The ideal gas equation is PV = nRT. In this equation, P denotes the ideal gas's pressure, V its volume, n its total amount, expressed in moles, and R its resistance for the universal gas constant, and T for temperature.
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C because I’m space there’s no gravity meaning things are weightless