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HACTEHA [7]
3 years ago
7

Which is a chemical property of soda ash?

Chemistry
2 answers:
PolarNik [594]3 years ago
5 0

Answer: Option (a) is the correct answer.

Explanation:

A property which can be observed when the chemical composition of the substance changes is referred to as chemical property.

For example, melting point, acidity, basicity, boiling point etc are all chemical properties of a substance.

In the given options, it's a white crystalline powder, it can dissolve in water and it can be separated from water by distillation, these all represent the physical property and no change in the chemical composition of soda ash.

Thus, we can conclude that it's a highly basic substance is a chemical property of soda ash.


Ede4ka [16]3 years ago
3 0
The best answer among the choices is the first option. The chemical property of soda is that it is a highly basic substance. Its chemical name is sodium carbonate. It is more basic than sodium bicarbonate. Adding soda ash in a solution would increase the pH of the solution.
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-2

Explanation:

Magnesium usually has a negative charge.

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3 years ago
If 2.0 ml of 6.0m hcl is used to make a 500.0-ml aqueous solution, what is the molarity of the dilute solution?
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Make sure that you understand what they are asking you from this question, as it can be confusing, but the solution is quite simple. They are stating that they want you to calculate the final concentration of 6.0M HCl once a dilution has been made from 2.0 mL to 500.0 mL. They have given us three values, the initial concentration, initial volume and the final volume. So, we are able to employ the following equation:

C1V1 = C2V2
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4 0
3 years ago
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7 0
2 years ago
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Find the equilibrium value of [CO] if Kc=14.5 : CO (g) + 2H2 (g) ↔ CH3OH (g) Equilibrium concentrations: [H2] = 0.322 M and [CH3
Annette [7]

Answer:

The equilibrium value of [CO] is 1.04 M

Explanation:

Chemical equilibrium is the state to which a spontaneously evolving  chemical system, in which a reversible chemical reaction takes place.  When this situation is reached, it is observed that the  concentrations of substances, both reagents and reaction products,  they remain constant over time. That is, the rate of reaction of reagents to products is the same as that of products to reagents.

Reagent concentrations  and products in equilibrium are related by the equilibrium constant Kc. Being:

aA + bB ⇔ cC + dD

Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }

Then this constant Kces equals the multiplication of the concentrations of the products raised to their stoichiometric coefficients between the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients.

In this case:

Kc=\frac{[CH_{3}OH ]}{[CO]*[H_{2} ]^{2} }

You know:

  • Kc= 14.5
  • [H₂]= 0.322 M
  • [CH₃OH] =1.56 M

Replacing:

14.5=\frac{1.56}{[CO]*0.322^{2} }

Solving:

[CO]=\frac{1.56}{14.5*0.322^{2} }

[CO]= 1.04 M

The equilibrium value of [CO] is 1.04 M

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