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deff fn [24]
3 years ago
11

A chemist has 20% and 50% solutions of acid available. How many liters of each solution should be mixed to obtain 75 liters of 2

8% acid solution?
Mathematics
1 answer:
mash [69]3 years ago
5 0

Answer:

we will mix 55 liters of 20% solution and 20 Liters of 50% solutions.

Step-by-step explanation:

let the 20% solution = x liters

let the 50% solution = y liters

total solution of the mixture of the two solutions in % = 28%

total solution of the mixture of the two solutions in liters = 75 liters

considering the total solutions given, we will have the following equations if we mix the solutions in equal proportion;

20x + 50y = 28 (75)

0.2x + 0.5y = 0.28(75)

0.2x + 0.5y = 21 -------equation 1

Also,

x + y = 75 ------equation 2

y = 75 - x  

(substitute this into equation 1)

0.2x + 0.5(75 - x) = 21

0.2x + 37.5 - 0.5x = 21

0.2x - 0.5x = 21 - 37.5

-0.3x = -16.5

x = -16.5 / -0.3

x = 55 liters

Recall, y = 75 - x

y = 75 -55

y = 20 Liters

Thus, we will mix 55 liters of 20% solution and 20 Liters of 50% solutions.

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