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Alika [10]
3 years ago
8

On may 1, 2008, the value of Noelles home was $223,770. On June 8, 2011, the value of her home had dropped by $31,250. By March

1, 2015, her home increased in value by $45,820. What was the value of her home in March 1, 2015?
Mathematics
1 answer:
babunello [35]3 years ago
5 0

Answer:

238,340

Step-by-step explanation:

223,770-31,250= 192,520 + 45,820= 238,340

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Solve for b.<br> 7<br> 10b+ 18 = 28<br> Answer: 6<br> Submit Answer
azamat

Answer:

False B=1

Step-by-step explanation:

10b+18=28

Subtract 18 both sides.

10b=10

Divide 10 both sides.

b=1

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I need help solving this
Tamiku [17]

Answer:

the correct answer is 302cm²

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SQRT is a parallelogram. If m∠QST = 72°, which of the following statements is true?
Mrrafil [7]
The answer to your question is option b because opposite angles in a quadrilateral are equal to one another
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Triangle P Q R is shown. The length of P Q is 20 and the length of P R is 12. Angle Q P R is 68 degrees and angle P Q R is 36 de
Tom [10]

Answer:

<h2> 112.3 square units</h2>

Step-by-step explanation:

Find the sketch of the triangle attached.

Area of the triangle = \frac{1}{2}|PQ| |PR| sinQPR

Given PQ = 20, PR = 12 and ∠QPR = 68°

Area of the triangle = 1/2 * 20 * 12 * sin68°

Area of the triangle = 120sin68°

Area of the triangle = 112.26 square units

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100 Brainliest up for grabs to person who can answer all of these with no links:
kogti [31]

Using a discrete probability distribution, it is found that:

a) There is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.

b) There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.

c) The expected value is of 1.3 lawns mowed on a randomly selected day.

<h3>What is the discrete probability distribution?</h3>

Researching the problem on the internet, it is found that the distribution for the number of lawns mowed on a randomly selected dayis given by:

  • P(X = 0) = 0.2.
  • P(X = 1) = 0.4.
  • P(X = 2) = 0.3.
  • P(X = 3) = 0.1.

Item a:

P(X = 2) = 0.3, hence, there is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.

Item b:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2 = 0.8

There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.

Item c:

The expected value of a discrete distribution is given by the <u>sum of each value multiplied by it's respective probability</u>, hence:

E(X) = 0(0.2) + 1(0.4) + 2(0.3) + 3(0.1) = 1.3.

The expected value is of 1.3 lawns mowed on a randomly selected day.

More can be learned about discrete probability distributions at brainly.com/question/24855677

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2 years ago
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