Math i am having a hard time doing this could anyone explain?

A bag of marbles contains 40 red marbles, 54 blue marbles, and 29 yellow marbles. Which of the following represents the ratio of

JulsSmile [24]

Answer:

$\frac{29}{40}$

Step-by-step explanation:

we know that

To find the ratio of yellow to red marbles, divide the numbers of yellow marbles by the number of red marbles

Let

x-----> the numbers of yellow marbles

y----> he number of red marbles

we have

$x=29, y=40$

so

$\frac{x}{y}=\frac{29}{40}$

8 0

2 years ago

The larger of two numbers is 1 more than twice the

stellarik [79]

Answer:

Step-by-step explanation:

Hi there!

Let the smaller number be x and the larger number be 2x+1.

According to the question,

The sum of the numbers is 20 less than three

times the larger.

i.e x + (2x+1)= 3*(2x+1) - 20

or, x + 2x +1 = 6x + 3 -20

or, 3x + 1 = 6x - 17

or, 3x = 18

or x= 18/3

x = 6

And 2x+1 = 2*6+1 = 13.

Therefore the smaller number is 6 and larger number is 13.

Hope it helps!

7 0

2 years ago

Can someone help please

elena-s [515]

Answer:

I'm sorry I can help you maybe a little bit if that's okay. Btw what grade are you in?

Step-by-step explanation:

3 0

2 years ago

Plz help plz plz plz plz

inysia [295]

................................................

The answer is 15.

8 0

2 years ago

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Select the correct answer. Which expression is equivalent to 8x^2^3 sqrt 375x + 2^3 sqrt 3x^7, if x=0?

natima [27]

Answer:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}$

Step-by-step explanation:

The question is poorly formatted. The original question is:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7$

We have:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7$

Open bracket

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^{3* \frac{2}{3}}) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

Express 8 as 2^3

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^{3* \frac{2}{3}} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^2 *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

Express 2^3 as 8

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{75x^3} + 8\sqrt{ 3x^7}$

Expand each exponent

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2 *3x} + 8\sqrt{ 3x * x^6}$

Split

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2} *\sqrt{3x} + 8\sqrt{3x} * \sqrt{x^6}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 *5x *\sqrt{3x} + 8\sqrt{3x} * x^3$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =20x^3\sqrt{3x} + 8x^3\sqrt{3x}$

Factorize

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}$

4 0

2 years ago

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