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3 years ago

(3-7n^2+3n^3)-(6n^3-1-5n^2). Simplify.

Mathematics

2 answers:

quester [9]3 years ago

5 0

Answer:

-3n^3 - 2n^2 + 4.

Step-by-step explanation:

(3-7n^2+3n^3)-(6n^3-1-5n^2)

First distribute the negative over the second parentheses:

= 3 - 7n^2 + 3n^3 - 6n^3 + 1 + 5n^2

Now simplify like terms:

= -3n^3 - 2n^2 + 4 (answer).

Burka [1]3 years ago

3 0

Simplify

3 - 7n^2 + 3n^3 - (6n^3 - 1 - 5n^2)

Simplify brackets

3 - 7n^2 + 3n^3 - 6n^3 + 1 + 5n^2

Collect like terms

(3 + 10) + (-7n^2 + 5n^2) + (3n^3 - 6n^3)

Simplify

4 - 2n^2 - 3n^3

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2 years ago

Solve for n 25/n = 5/8

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2 years ago

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What is five x plus negative three equals fifteen

bearhunter [10]

You write the equation like this:
$5x + (-3) = 15$

But if you want to solve it then you do it like this:
$5x + (-3) = 15$
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3 years ago

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Select all the statements that are true for the graph shown.

Yuki888 [10]

Answer:

The relationship is proportional.

The relationship is linear.

The equation of the line is y = –3x.

Step-by-step explanation:

The line in the question passes through origin and (4,-12).

The rate of change of the line is

$m=\dfrac{-12-0}{4-0}\\\Rightarrow m=\dfrac{-12}{4}\\\Rightarrow m=-3$

The rate of change of the line or slope of the line is -3

Equation of the line is given by

$(y-0)=-3(x-0)\\\Rightarrow y=-3x$

This means that the relationship is linear.

If we take any value of x then there will be only one value of y this means that the relationship is proportional.

So the following statements are true

The relationship is proportional.

The relationship is linear.

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2 years ago

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What is the cube root of 27a^l2? -3a4 -3a 3a 3a*

GuDViN [60]

Answer:

$3a^4$

Step-by-step explanation:

What is the cube root of $27a^{12}$ ? This is the question.

We can write:

$\sqrt[3]{27a^{12}}$

We will use the below property to simplify:

$\sqrt[n]{a*b}=\sqrt[n]{a} \sqrt[n]{b}$

So, we have:

$\sqrt[3]{27a^{12}} =\sqrt[3]{27} \sqrt[3]{a^{12}}$

We will now use below property to further simplify:

$\sqrt[n]{x} =x^{\frac{1}{n}}$

Thus, we have:

$\sqrt[3]{27} \sqrt[3]{a^{12}} =3*(a^{12})^{\frac{1}{3}}$

We know power to the power rule: $(a^z)^b=a^{zb}$

Now, we have:

$3*(a^{12})^{\frac{1}{3}}\\=3*a^{\frac{12}{3}}\\=3a^4$

This is the correct answer: $3a^4$

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3 years ago