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lesya [120]
3 years ago
8

5th grade math lesson 7.9 a vet weighs 2 puppies. The small puppy weighs 4 1/2 pounds. The large puppy weighs 42/3 times as much

as the small puppy. How much does the small puppy weigh
Mathematics
2 answers:
Korvikt [17]3 years ago
7 0

The large puppy weighs 4 1/2 x 42/3 pounds.

4 1/2 x 42/3 = 9/2 x 42/3 = 63 pounds

answer: 63 pounds for the large puppy

Natalka [10]3 years ago
6 0

Answer:the large puppy weighs 63 pounds.

Step-by-step explanation:

A vet weighs 2 puppies. The small puppy weighs 4 1/2 pounds. Converting 4 1/2 pounds to improper fraction, it becomes 9/2 pounds.

The large puppy weighs 42/3 times as much as the small puppy. This means that the number of pounds that the large puppy weighs would be

42/3 × 9/2 = 63

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Point (2, -4) is reflected across the x-axis. What are<br> the coordinates of its image?
Zina [86]

The coordinates of the image of point (2 , -4) after reflection across

the x-axis is (2 , 4)

Step-by-step explanation:

Let us revise the reflection of a point

1. If point (x , y) reflected across the x-axis, then its image is (x , -y)

2. If point (x , y) reflected across the y-axis, then its image is (-x , y)

3. If point (x , y) reflected across the line y = x, then its image is (y , x)

4. If point (x , y) reflected across the line y = -x, then its image is (-y , -x)

∵ Point (2, -4) is reflected across the x-axis

∵ Point (x , y) reflected across the x-axis, then its image is (x , -y)

- Chang the sign of the y-coordinate of the point to find its image

∵ The y-coordinate of the point is -4

∴ The y-coordinate of the image is 4

∴ The image of the point (2 , -4) is (2 , 4) after reflection across the

   x-axis

The coordinates of the image of point (2 , -4) after reflection across

the x-axis is (2 , 4)

Learn more:

You can learn more about reflection in brainly.com/question/5017530

#LearnwithBrainly

7 0
2 years ago
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Help please quick please
qaws [65]

Answer:

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Step-by-step explanation:

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3 years ago
A random sample of 11 days were selected from last year's records maintained by the maternity ward in a local hospital, and the
EleoNora [17]

Answer: ( Min = 0 , Q_1=1 , Q_2=3 , Q_3=7 , Max = 10 )

Step-by-step explanation:

Given : A random sample of 11 days were selected from last year's records maintained by the maternity ward in a local hospital, and the number of babies born each day of the days is given below:

3  7   7   10    0    7    1    2    5   3    0

We first arrange them in increasing order , we get

0    0    1    2   3   3   5     7   7   7   10

Here , N= 11

Now , we can see that

Minimum value = 0

Maximum value = 10

First quartile Q_1= (\dfrac{N+1}{4})^{th}\ term=(\dfrac{12}{4})^{th}\ term = 3^{rd} term =1

Second quartile Q_2= Median = Middlemost number = 3

Third quartile Q_3 =  (\dfrac{3(N+1)}{4})^{th}\ term=(\dfrac{36}{4})^{th}\ term

= 9^{th} term =7

∴ The required five number summary : ( Min = 0 , Q_1=1 , Q_2=3 , Q_3=7 , Max = 10 )

7 0
2 years ago
Will you help out with this equation please
Rina8888 [55]
If that says 4v=3 and 2/3, then v =11/12
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2 years ago
The sum of two times a number and six is equal to two times the sum of a number and three
Serhud [2]

2x+6=2(x+3)

Step-by-step explanation:

let x represent the unknown number

7 0
3 years ago
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