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3 years ago

Name the quadrilaterals that have four equal angles.

Mathematics

2 answers:

Alex73 [517]3 years ago

7 0

B. square, rectangle

weqwewe [10]3 years ago

6 0

The answer is a .......

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Solve for y <br> Please i need help

Nataly [62]

Answer:

y = 1/9

Step-by-step explanation:

Use distributive property and simplify!

5 0

3 years ago

Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$

Simplify the radical with the cube:

$\displaystyle x^3=\frac{3y+16}{2y+9}$

Multiply by 2y+9

$\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)$

Simplify:

$\displaystyle x^3(2y+9)=3y+16$

Operate the parentheses:

$\displaystyle x^3(2y)+x^3(9)=3y+16$

$\displaystyle 2x^3y+9x^3=3y+16$

Subtract 3y and $9x^3$ :

$\displaystyle 2x^3y - 3y=16-9x^3$

Factor y out of the left side:

$\displaystyle y(2x^3 - 3)=16-9x^3$

Divide by $2x^3 - 3$ :

$\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}$

ii) To find y when x=2, substitute:

$\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}$

$\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}$

$\displaystyle y=\frac{16-72}{16- 3}$

$\displaystyle y=\frac{-56}{13}$

$\mathbf{\displaystyle y=-\frac{56}{13}}$

8 0

2 years ago

What is the equation in slope-intercept form of the line that passes through the points (-4, 2) and (12, 6)?

BartSMP [9]

Answer:

Step-by-step explanation:

8 0

2 years ago

Can someone explain how to do this?

Tems11 [23]

x+7
------------------- =
x^2+4x -21

x+7
= -------------------
   (x+7)(x-3)

1
= ----------  where x is not equal -7 and 3
   x - 3

answer is A. first choice

4 0

3 years ago

Kirk went to a friend’s house after dinner. He left his house at 7:29pm and returned home at 8:05pm. How long was Kirk gone for?

liberstina [14]

Answer:

36 minutes

Step-by-step explanation:you look at it and solve it

3 0

3 years ago

Read 2 more answers