Which equations are true for x = –2 and x = 2? Check all that apply.

1 answer:

4 0

А. х²-4=0; х²=4; х=±2, true. B. x²=-4; there is no solution. C. 3x²+12=0; 3x²=-12; x²=-4; there is no solution. D. 4x²=16; x²=4; x=±2, true. E. 2(x-2)²=0; 2(x²-4x+4)=0; 2x²-8x+8=0; x²-4x+4=0; x1=2; x2=2. False. The answer: A, D.

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How do i solve this question

frozen [14]

$\bf \begin{cases}
h(x)=(f\circ g)(x)\\
h(x)=\sqrt{x+5}\\
f(x)=\sqrt{x+2}
\end{cases}\\\\
-------------------------------\\\\
(f\circ g)(x)\implies f[\ g(x)\ ]\implies f[\ g(x)\ ]=\sqrt{g(x)+2}\qquad thus
\\\\\\
\sqrt{g(x)+2}=(f\circ g)(x)=h(x)=\sqrt{x+5}\qquad therefore
\\\\\\
\sqrt{g(x)+2}=\sqrt{x+5}\impliedby \textit{squaring both sides}\\\\\\
g(x)+2=x+5\implies g(x)=x+5-2\implies \boxed{g(x)=x+3}$

8 0

3 years ago

Solve each quadratic equation. Show your work.

umka2103 [35]

14. 2x-1 = 0, x+7=0
x = 1/2, x = -7

15. x^2 + 3x - 10 = 0
(x + 5)(x - 2) = 0
x = -5, x = 2

16. x^2 - 25 = 0
(x-5)(x+5)
x = 5, x = -5

5 0

3 years ago

Which function could be represented by the graph on the coordinate plane?

spin [16.1K]

Answer:

$\boxed{f(x)=(x-8)^2-6}$

Step-by-step explanation:

The graph in the attachment is a quadratic function whose vertex is in the fourth quadrant.

The coordinates of a point in the fourth quadrant is of the form $(x,-y)$

Considering the options, the vertex must have coordinates $(h,k)=(8,-6)$ and $a=1$ .

The quadratic function in vertex form is written as;

$f(x)=a(x-h)^2+k$

Therefore the equation of the quadratic function is;

$f(x)=(x-8)^2-6$

The correct answer is option D

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3 years ago

The first term of an arithmetic sequence is 4. The

Sliva [168]

-1 i think that the answer is -1

5 0

3 years ago

ΔABC is a right triangle in which is a right angle, AB = 1, AC = 2, and BC = .

ollegr [7]

We are asked to solve for the measurement of side BC in the given right triangle ΔABC and other side measurements were also given such as AB=1 and AC = 2. Since this is a right triangle, we can use and apply the Pythagorean theorem c²= a² + b² and the solution is shown below:
c = AC
b = BC
a = AB
AC² = AB² + BC² , substitute values we have:
2² = 1² + BC²
BC² = 4-1
BC = √3
BC = 1.732

The answer for the length of BC is 1.732 units.

8 0

3 years ago