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OlgaM077 [116]
3 years ago
11

True or false a reflection across the line y=-x

Mathematics
2 answers:
Sauron [17]3 years ago
6 0

Answer: False

Step-by-step explanation:

dedylja [7]3 years ago
4 0

Answer:

True

Step-by-step explanation:

The negative sign reflect the graph over x-axis.

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Find the midpoint of the segment with the given endpoints. (-10.2) and (0,-7)​
iris [78.8K]

Answer:

=\left(-5,\:-\frac{5}{2}\right)

Step-by-step explanation:

\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(-10,\:2\right),\:\left(x_2,\:y_2\right)=\left(0,\:-7\right)\\\\=\left(\frac{0-10}{2},\:\frac{-7+2}{2}\right)\\\\= (\frac{-10}{2} , \frac{-5}{2})\\ \\=\left(-5,\:-\frac{5}{2}\right)

7 0
2 years ago
The nature of a graph, which has an even degree and a positive leading coefficient will be
zaharov [31]

The nature of a graph, which has an even degree and a positive leading coefficient will be<u> up left, up right</u> position

<h3 /><h3>What is the nature of the graph of a quadratic equation?</h3>

The nature of the graphical representation of a quadratic equation with an even degree and a positive leading coefficient will give a parabola curve.

Given that we have a function f(x) = an even degree and a positive leading coefficient. i.e.

  • y = f(x) = 2x²+ 4

The domain of this function varies from -∞ < x < ∞ and the parabolic curve will be positioned on the upward left and upward right x-axis.

Learn more about the graph of a quadratic equation here:

brainly.com/question/9643976

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Which ordered pair would represent the points that would lie on the graph y=3/4x+3?
Nastasia [14]
Is there a list of answers ?
4 0
3 years ago
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