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Ber [7]
3 years ago
15

Given a sphere with a radius of 2 cm, find its volume to the nearest whole

Mathematics
1 answer:
nirvana33 [79]3 years ago
6 0

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=2 \end{cases}\implies V=\cfrac{4\pi (2)^3}{3}\implies V=\cfrac{32\pi }{3} \\\\\\ V\approx 33.51032163829112\implies \stackrel{\textit{rounded up}}{V=34}

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<u>Solution</u><u>:</u>

\sqrt{4x + 13}  = x + 2

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=  > ( \sqrt{4x + 13} ) ^{2}  = (x + 2) ^{2}

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=  > 4x + 13 =  {(x)}^{2}  + 2 \times x \times 2 + (2) ^{2} \\  =  > 4x + 13 =  {x}^{2}   + 4x + 4

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=  > 4x - 4x + 13 - 4 =  {x}^{2}  \\

  • Now, do the addition and subtraction.

=  >  {x}^{2}  = 9 \\  =  >  x =  \sqrt{9}  \\  =  > x = ±3

<u>Answer</u><u>:</u>

<u>x </u><u>=</u><u> </u><u>±</u><u> </u><u>3</u>

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The answer is D. Surface Tension. :) I am forsure this is correct but please let me know. If I am correct please rate me 5 and thank me and mark me brainlest :)

Step-by-step explanation:


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