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andrezito [222]
3 years ago
12

(EXTRA POINTS) Which of the following relations is a function? file in question

Mathematics
1 answer:
Taya2010 [7]3 years ago
6 0
I think it is a I am not sure though
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What is the difference between the mean and median (rounded to the nearest tenth) of these numbers 6,6,6,7,7,7,8,8,8,9
Nadusha1986 [10]

The median is the moddle number of a data set. If the number of numbers is even add the 2 middle numbers and divide by 2.

Median = (7+7)÷2 = 7

The mean is the averagw value in a data set. You find it be adding all the numbers and then divide the answer by the number of numbers.

Mean: (6+6+6+7+7+7+8+8+8+9) ÷ 10

= 72 ÷ 10 = 7.2

Happy to help! Marking my answer as the Brainliest would really be aprreciated.

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Alec's total payment for his loan was $19,440. what was his monthly payment if he paid it off after making 60 monthly payments?
horsena [70]
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Is a simple random sample is valid true or never true or always or sometimes
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What is the inverse of f(x)=(3x+2)/(5x-2)?
yKpoI14uk [10]

Answer:

y= 2x=2/5x - 3

Step-by-step explanation:

swap the variables: y=3x+25x−2 becomes x=3y+25y−2.

Now, solve the equation x=3y+25y−2 for y.

8 0
3 years ago
The diagram shows a square ABCD with sides of length 20cm. it also shows a semi circle and an arc circle AB is the diameter of t
Brut [27]

Answer:

Area of Shaded Region =50\pi$ cm^2

Area of Semicircle =50\pi$ cm^2

\dfrac{\text{Area of Shaded region}}{\text{Area of Square}}=\dfrac{ \pi}{8}

Step-by-step explanation:

Area of Shaded Region = Area of Sector - Area of Semicircle

<u>Area of Sector</u>

Radius of the sector =20cm

=\frac{90}{360}X\pi *20^2\\ =100\pi cm^2

<u>Area of Semicircle</u>

Since AB is the diameter of the semicircle

Radius of the Semicircle=20/2=10cm

Area of semicircle

=\frac{\pi r^2}{2}\\ =\frac{\pi *10^2}{2}\\=50\pi cm^2

Therefore, area of Shaded Region

=100\pi -50 \pi\\=50\pi$ cm^2

Area of Square =20 X 20 =400 cm^2

\dfrac{\text{Area of Shaded region}}{\text{Area of Square}} \\=\dfrac{50 \pi}{400} \\=\dfrac{ \pi}{8}

4 0
3 years ago
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