4 years ago

(EXTRA POINTS) Which of the following relations is a function? file in question

Mathematics

1 answer:

Taya2010 [7]4 years ago

6 0

I think it is a I am not sure though

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NNADVOKAT [17]

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Step-by-step explanation:

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4 years ago

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The grades for class are as follows: 10 A's, 8 B's, 6 C's, 5 D's What percent received an A? (round to the nearest whole )

boyakko [2]

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3 years ago

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3 years ago

Sin A tan A/ 1 - cos A = 1+ sec A

aalyn [17]

$\text{L.H.S}\\\\=\dfrac{\sin A \tan A}{1- \cos A}\\\\\\=\dfrac{\sin A \cdot \tfrac{\sin A}{\cos A} }{ 1- \cos A}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~;\left[\tan A = \dfrac{\sin A }{\cos A}\right]\\\\\\=\dfrac{\tfrac{\sin^2 A}{ \cos A}}{1- \cos A}\\\\\\=\dfrac{\sin^2 A}{\cos A(1-\cos A)}\\\\\\=\dfrac{1-\cos^2 A}{\cos A( 1- \cos A)}~~~~~~~~~~~~~~~~~~~~~~~~;[\sin^2 A + \cos^2 A = 1]\\\\\\$

$=\dfrac{(1+ \cos A)(1 - \cos A)}{\cos A(1 - \cos A)}\\\\\\=\dfrac{1+ \cos A}{ \cos A}\\\\\\=\dfrac{1}{\cos A} + \dfrac{\cos A}{ \cos A}\\\\\\=\sec A + 1 \\\\\\=1+ \sec A\\\\\\=\text{R.H.S}\\\\\text{Proved.}$

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2 years ago