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4 years ago

Please help find the amount of interior angles in the shape.

Mathematics

1 answer:

gladu [14]4 years ago

8 0

The polygon has 11 sides.

The measure each interior angle is 147.272°.

Solution:

The given shape is a regular polygon.

(a) Number of sides of the polygon = 11

The polygon has 11 sides.

(b) To find the measure of each interior angle:

Each interior angle of a regular polygon

$$=\frac{(n-2) \times 180^{\circ}}{n}$

$$=\frac{(11-2) \times 180^{\circ}}{11}$

$$=\frac{9 \times 180^{\circ}}{11}$

$=147.272^\circ$

The measure each interior angle is 147.272°.

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What is the equation of a line, in the general form, with a slope of-2an a y-intercept of 8? 1) x+2y-8=0, 2) 2x+y-8=0, 3) 2x-y+8

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3 years ago

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A ball is launched upward at 14 m/s from a platform 30 m high.Find the maximum height the ball will reach and how long it will t

BartSMP [9]

Answer:

The ball will reach a maximum height of 39.993 meters after 1.428 seconds.

Step-by-step explanation:

Let suppose that no non-conservative forces acts on the ball during its motion, then we can determine the maximum height reached by the Principle of Energy Conservation, which states that:

$K_{1}+U_{g,1} = K_{2}+U_{g,2}$ (1)

Where:

$K_{1}$ , $K_{2}$ - Initial and final translational kinetic energies, measured in joules.

$U_{g,1}$ , $U_{g,2}$ - Initial and final gravitational potential energies, measured in joules.

By definition of translational kinetic energy and gravitational potential energy we expand and simplify the expression above:

$\frac{1}{2}\cdot m\cdot v_{2}^{2}+m\cdot g\cdot y_{2}= \frac{1}{2}\cdot m\cdot v_{1}^{2}+m\cdot g\cdot y_{1}$ (2)

Where:

$m$ - Mass of the ball, measured in kilograms.

$g$ - Gravitational acceleration, measured in meters per square second.

$v_{1}$ , $v_{2}$ - Initial and final speed of the ball, measured in meters per second.

$y_{1}$ , $y_{2}$ - Initial and final heights of the ball, measured in meters.

The final height of the ball is determined by the following formula:

$v_{2}^{2}+2\cdot g\cdot y_{2} = v_{1}^{2}+2\cdot g\cdot y_{1}$

$v_{1}^{2}-v_{2}^{2}+2\cdot g \cdot y_{1}=2\cdot g\cdot y_{2}$

$y_{2} = y_{1}+\frac{v_{1}^{2}-v_{2}^{2}}{2\cdot g}$ (3)

If we know that $y_{1} = 30\,m$ , $v_{1} = 14\,\frac{m}{s}$ , $v_{2} = 0\,\frac{m}{s}$ and $g = 9.807\,\frac{m}{s^{2}}$ , the maximum height that the ball will reach is:

$y_{2} = 30\,m + \frac{\left(14\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)}$

$y_{2} = 39.993\,m$

The ball will reach a maximum height of 39.993 meters.

Given the absence of non-conservative forces, the ball exhibits a free fall. The time needed for the ball to reach its maximum height is computed from the following kinematic formula:

$t = \frac{v_{2}-v_{1}}{-g}$ (4)

If we know that $v_{1} = 14\,\frac{m}{s}$ , $v_{2} = 0\,\frac{m}{s}$ and $g = 9.807\,\frac{m}{s^{2}}$ , then:

$t = \frac{0\,\frac{m}{s}-14\,\frac{m}{s} }{-9.807\,\frac{m}{s^{2}} }$

$t = 1.428\,s$

The ball will take 1.428 seconds to reach its maximum height.

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anastassius [24]

Answer:

The functions with the property f(–x) =f(x) are called even functions because they symmetric about the y-axis and The functions with the property f(–x) = -f(x) are called odd because these function are symmetric about the origin .

Step-by-step explanation:

The functions with the property f(–x) =f(x) are called even functions because they symmetric about the y-axis . In other words these functions usually take a form x^2 ,x^4 ,x^6 ,x^8 etc . However ,there are other functions that behave like that too, such as cos(x).An even exponent does not always make an even function, for example (x+1)^2 is not an even function .

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3 years ago