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Oksanka [162]
2 years ago
9

Find the length of the missing side of the trapezoid below.

Mathematics
1 answer:
Semmy [17]2 years ago
8 0

Answer:

2√10

Step-by-step explanation:

Draw a vertical line through the corner between the side of length 7 and the side of length 5.  This line forms a right triangle with hypotenuse 7 and base (8 - 5), or 3.

The Pythagorean Theorem applies here.  

(hypotenuse)² = (base)² + (vertical side)²    and this becomes:

          7² = 3² + (vertical side)²

Solving this for (vertical side)², we get (vertical side)² = 49 - 9 = 40.

Thus, (vertical side) = √40 = √4·√10 = 2√10 (answer)

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Answer:

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Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
A ramp is 17 ft long , rises 8 ft above the floor, and covers a horizontal distance of 15 ft,as shown in the figure
gavmur [86]

A ramp is 17 feet long, rises 8 feet above the floor,

and covers a horizontal distance of 15 feet,

as shown in the figure.

(First box)

A. Sin B = 8/17

B. Cos B = 15/17

C. Sin A = 15/17

(Second box)

A. Sin B = 8/17

B. Cos B = 15/17

C. Cos A = 8/17

Hope this helps!

8 0
3 years ago
What is an equivalent fraction for the following fraction?<br> 5/8....<br> 09/16<br> 8/16<br> 10/16
atroni [7]

Answer:

10/16

Step-by-step explanation:

I looked at the 5 and looked at every other number and you can't multiply evenly with those other numbers. You can only do 5x2 which will get you ten. But that won't work for the other numbers.

Hope this helps :)

4 0
3 years ago
Hence, Solve the equation<br>X Х<br>1- x<br>4x=​
raketka [301]
I’m not sure I understand what’s going on here. But if you’re saying x=1, and the problem is 4x=?. Then 4(1)=4
3 0
2 years ago
suppose you have a dime, two pennies, and a quarter. one of the pennies was minted in 1976, and the other one was minted in 1992
notsponge [240]

The reason that the answers in part (a) and part (b) are not the same is because Q1 and Q2 are treated as two different coins in part (a) whereas they are effectively treated as the same coin in part (b). The reason they are treated as one coin is because they both contribute the same amount to the sum of money.

<h3>How to Solve Counting Problems?</h3>

A) If you choose at least one coin, this means you could choose 1, 2, 3 or 4 coins. Let us label the dime as D, the penny as P, the quarter minted in 1976 as Q1 and the quarter minted in 1992 as Q2.

Now, if you choose one coin, you could choose either D, P, Q1, or Q2. This gives us 4 possible sets.

If you choose two coins, you choose the following sets of coins: DP, DQ1, DQ2, PQ1, PQ2, Q1Q2. This gives us 6 possible sets.

If you choose three coins, you could the following sets of coins: DPQ1, DPQ2, DQ1Q2, PQ1Q2. This gives us 4 possible sets.

If you choose four coins, you can only choose DPQ1Q2. This gives us 1 possible set.

Therefore, the total number of different sets of coins you can form is 4 + 6 + 4 + 1 = 15 different sets of coins can be formed.

b) If you choose at least one coin, this means you could choose 1, 2, 3 or 4 coins.

If you choose one coin you could choose either D, P, Q1, or Q2. However, since Q1 and Q2 give us the same sum, they are effectively the same set. This gives us 3 possible sums (ten cents, one cent, or twenty-five cents.)

If you choose two coins, you could choose the following sets of coins (since Q1 and Q2 are the same coin value, we can say Q for any instance where either one of these coins would be a possibility): DP, DQ, PQ, Q1Q2. This gives us 4 possible sums (11 cents, 35 cents, 26 cents, or fifty cents.)

If you choose three coins, you could choose the following sets of coins (since Q1 and Q2 are the same coin value, we can say Q for any instance where either one of these coins would be a possibility): DPQ, DQ1Q2, PQ1Q2. This gives us 3 possible sums (36 cents, 60 cents, or 51 cents).

If you choose four coins, you can only choose DPQ1Q2. This gives us 1 possible sum (61 cents.)

Therefore, the total number of different sums of coins you can form is 3 + 4 + 3 + 1 = 11 different sums of money can be produced.

c) The reason that the answers in part (a) and part (b) are not the same is because Q1 and Q2 are treated as two different coins in part (a) whereas they are effectively treated as the same coin in part (b). The reason they are treated as one coin is because they both contribute the same amount to the sum of money.

Read more about Counting Problems at; brainly.com/question/13875198

#SPJ1

3 0
1 year ago
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