If tan x = m, what is sin x in terms of m?

Mathematics

1 answer:

zubka84 [21]2 years ago

5 0

Answer: m/sqrt(m^2)+1

Step-by-step explanation: if tan x = m, then the opposite angle is m and the adjacent angle is 1 so 1 squared plus m squared equals c squared. c = sqrt (1 + m^2)

sin x = opposite/hypotenuse = m/sqrt(m^2)+1

You might be interested in

Find the value for d 2d - 5 = 17

Ann [662]

2d-5=17

2d=17+5

2d=22
— —
2 2

d=11

4 0

2 years ago

Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$

Blizzard [7]

$\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}$

$a^{81}\equiv1^{81}\equiv1\pmod7$

$b^{91}\equiv2^{91}\pmod7$

$2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7$
$8\equiv1\pmod7$
$2\equiv2\pmod7$
$\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7$

$c^{27}\equiv6^{27}\pmod7$

$6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7$

$\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7$