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Nataliya [291]
3 years ago
12

If I have the height and volume of a cylinder, how do I find the radius? or diameter?

Mathematics
2 answers:
kondor19780726 [428]3 years ago
8 0
V=\pi r^2h\\
r^2=\frac{V}{\pi h}\\
r=\sqrt{\frac{V}{\pi h}}

Anna71 [15]3 years ago
6 0
If you have the volume, that's a pretty good giveaway that you ought to use
the formula for the volume of a cylinder, since it involves all the other things ...
the things you're given, and the things you need to find.  If you know the formula
for the volume of a cylinder, you can whip out the answer in a second.  If you don't
know the formula, then you are toast.

Volume of a cylinder = (pi) (radius)² (length or height)

Divide each side of the equation by (pi) x (height) and you have

(Radius)² = Volume / (pi x height)

You HAVE volume and height, so you can use this equation to calculate
the radius.  Once you have that, if you need the diameter, it's just double
the length of the radius.

That's how.
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Natali [406]

Answer:

its not b but i think its c

Step-by-step explanation:

because it is

8 0
3 years ago
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Compare and Contrast how you would factor x^2−9 and x^2+9. For full credit, make sure you explain why they are factored differen
marishachu [46]

The factored form of the expression x^2 - 9 is (x+3)(x-3)

The expression x^2 + 9 has no real roots hence cannot be factored

Quadratic equations are equations with a degree of 2.

Given the quadratic function x^2-9 \ and \ x^2+9

For the function x^2 - 9

=x^2-9\\=x^2-3^2

Using the difference of two squares:

a^2-b^2=(a-b)(a+b)\\x^2-3^2=(x-3)(x+3)

For the expression x^2 + 9

The expression x^2 + 9 has no real roots hence cannot be factored

Learn more on factorization here: brainly.com/question/20293447

7 0
2 years ago
How to solve this? ​
nevsk [136]

Answer:

Answer of 17 is ㏒(x^{2}+15x), Answer of 33 is x = 8 , Answer of 35 is x = ㏒10/㏒2 , Answer of 37 is  x = -㏒12/㏒8 and Answer of 39 is x = 5

Step-by-step explanation:

17. ㏒x + ㏒(x+15)

     Using property ㏒a + ㏒b = ㏒a×b

     ∴ ㏒x + ㏒(x+15)

        ㏒x×(x+15)

        ㏒(x^{2}+15x)

        The answer is ㏒(x^{2}+15x)

33. 2^(x-5) = 8

     2^(x-5) = 2^3

      Using property 2^a = 2^b

      Then a = b

     ∴x-5 = 3

       x = 8

      The answer is x = 8

35. 2^x = 10

    Taking log on both sides gives

     ㏒2^x = ㏒10

     x×㏒2 = ㏒10

     x = ㏒10/㏒2

    The answer is x = ㏒10/㏒2

37. 8^-x = 12

    Taking log on both sides gives

     ㏒8^-x = ㏒12

     -x×㏒8 = ㏒12

      x = -㏒12/㏒8

    The answer is  x = -㏒12/㏒8

39. 5(2^3 × x) = 8

      5(8×x) = 8

      x = 5

    The answer is x=5

 

5 0
3 years ago
Carlos Martin received a statement from his bank showing a balance of $56.75 as of March 15th his check book shows a balance of
kakasveta [241]

Answer:

$48.87

Step-by-step explanation:

Let the deposited amount between the March 15th and the March 20th be x

Balance on 15th march =  $56.75

The bank returned all the cancelled checks but too. One check was for $5 and the other was for $13.25

And he also deposited x amount

After deposits and deductions

So, balance = 56.75 +x - (13.25+5)

The new balance on 20th march =  $87.37

⇒56.75 +x - (13.25+5)=87.37

⇒56.75 +x - 18.25=87.37

⇒38.5 +x =87.37

⇒x =87.37-38.5

⇒x =48.87

Hence Carlos deposited  $48.87  in his account between the March 15th and the March 20th.

6 0
2 years ago
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Gennadij [26K]

Answer:

m²

Step-by-step explanation:

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