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3 years ago

If I have the height and volume of a cylinder, how do I find the radius? or diameter?

Mathematics

2 answers:

kondor19780726 [428]3 years ago

8 0

$V=\pi r^2h\\
r^2=\frac{V}{\pi h}\\
r=\sqrt{\frac{V}{\pi h}}
$

Anna71 [15]3 years ago

6 0

If you have the volume, that's a pretty good giveaway that you ought to use
the formula for the volume of a cylinder, since it involves all the other things ...
the things you're given, and the things you need to find. If you know the formula
for the volume of a cylinder, you can whip out the answer in a second. If you don't
know the formula, then you are toast.

Volume of a cylinder = (pi) (radius)² (length or height)

Divide each side of the equation by (pi) x (height) and you have

(Radius)² = Volume / (pi x height)

You HAVE volume and height, so you can use this equation to calculate
the radius. Once you have that, if you need the diameter, it's just double
the length of the radius.

That's how.

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luda_lava [24]

Answer:

Step-by-step explanation:

1. $7x^3y+14x^2y^3-7x^2y^2$

The GCF of all the term of the above polynomial is $7x^2y$ , hence we take it outside and form a bracket

$7x^2y(x+2y^2-y)$

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer

2. $5x(x+3)+6(x+3)$

The GCF of all the term of the above polynomial is $(x+3)$ , hence we take it outside and form a bracket

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The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer

3. $8x^5+2x^4+4x^2$

The GCF of all the term of the above polynomial is $2x^2$ , hence we take it outside and form a bracket

$2x^2(4x^3+x^2+2)$

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (D) is the right answer

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2 years ago

Prove that : sinA/1+cosA + 1+cosA/sinA=2cosecA

tekilochka [14]

Step-by-step explanation:

$\frac{sinA}{1+cosA} +\frac{1+cos}{sinA} =2cosec\\\\\\\frac{sin^{2}A+(1+cos)^{2} }{sinA(1+cosA)} \\\\$

$\frac{sin^{2}A+1+cos^{2}+2cos}{sinA(1+cosA)} \\\\$ and we have $sin^{2}+cos^{2} =1$

so $\frac{1+1+2cosA }{sinA(1+cosA)} \\\\$

$\frac{2+2cosA }{sinA(1+cosA)} \\\\$

$\frac{2(1+cosA)}{sinA(1+cosA)} \\\\$

$\frac{2}{sinA}$ we have $\frac{1}{sin}=cosec\\$

Finally $2cosecA$

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2 years ago

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larisa [96]

The answer is 5
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2 years ago

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Katyanochek1 [597]

Answer:

There is not enough information for this problem, can you provide more information?

Step-by-step explanation:

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2 years ago

Construct a circle with a radius of 8cm, and draw an equilateral triangle inside it. Make sure the length of each side measures

Ipatiy [6.2K]

Answer:

Diagram 1

Draw a circle with a radius of 8 cm, ensuring you have clearly marked the center point (black circle with center C1)

Add a point on the circumference of the circle (point C2)

Draw a second circle of radius 8cm with point C2 as its center (red circle with center C2).

Diagram 2

The red circle intersects the black circle at two points (D and E).

Connect these 2 points of intersection with a line segment.

Diagram 3

Draw a third circle with center D and radius DE (shown in blue)

This circle intersects the black circle at point F.

Diagram 4

Draw 2 line segments to connect points D and E with point F - this is your equilateral triangle inside the circle!

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2 years ago