I will mark brainliest .. please help me with this equation because i'm not smart.. xD
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We can use the ratios for special triangles (see the attachment below). We'll be using the 45-45-90 triangle. We notice that side BC is equal to 
, and side AC (x using the special right triangle) is equal to 16. We can therefore say that side BC is equal to 
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Hi there!
To solve, we can use right triangle trigonometry.
Recall that:
sin = O/H, cos = A/H, tan = O/A.
For angle G, HF is its OPPOSITE side, and FG is the hypotenuse.
Therefore, we must use sine to evaluate:
sinG = 14 / 17
sin⁻¹ (14/17) = ∠G. Evaluate using a calculator.
∠G ≈ 55.44°