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Nimfa-mama [501]
3 years ago
11

OMG GUYS HELP ASAP!!!! THIS IS MY HW ALSO!

Mathematics
1 answer:
natka813 [3]3 years ago
3 0
One point: draw the line a bit lower such that it touches the circle. A line from the center of the circle to the line will be perpendicular to it.

Two points: draw the line somewhere through the circle. There will be two intersection points.

Three points: can't be done.
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7 0
3 years ago
COSO ---
Vsevolod [243]

Answer:

• zero: -4, -4/3, 7

• positive: -4 < x < -4/3 . . . or 7 < x

• negative: x < -4 . . . or -4/3 < x < 7

Step-by-step explanation:

Zeros of the function are at x=-4, -4/3, +7. These are the values that make each of the individual factors be zero. For example, x-7=0 when x=7.

The function will be negative for x-values left of an odd number of zeros. It will be positive for x-values left of an even number of zeros (including left of no zeros, which is to say right of all zeros). This is because the sign of the factor giving rise to the zero changes for x-values on either side of that zero. (This is not true for zeros with even multiplicity, as the sign does not change at those.)

3 0
3 years ago
Find the equation of the line that passes through the points : (4 , -1 ) and (0 , -3)
Sergio [31]

Answer:

B. y= 1/2 x - 3

Step-by-step explanation:

base equation: y= mx+ b

slope(m) equation: \frac{y_{2}-y_{2}  }{x_{2} -x_{1} }

y2= -1    y1= -3

x2= 4     x1= 0

\frac{-1 - (-3)}{4-0} =\frac{2}{4} = \frac{1}{2}

y- intercept: -3

found by taking the y from (0,-3)

3 0
3 years ago
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