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Ghella [55]
3 years ago
6

Change 72 out of 123 to a percentage

Mathematics
1 answer:
Elanso [62]3 years ago
4 0

Answer:

72 / 123 * 100 = 58.53658537  per cent

Step-by-step explanation:

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Step-by-step explanation:

Area = (17×35) - (6×15) = 595 - 90 = 505 ft²

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Cable Strength: A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the ca
KatRina [158]

Answer:

95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

Step-by-step explanation:

We are given that the engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb.

Since, in the question it is not specified that how much confidence interval has be constructed; so we assume to be constructing of 95% confidence interval.

Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;

                            P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean breaking weight = 768.2 lb

            s = sample standard deviation = 15.1 lb

            n = sample of cables = 45

            \mu = population mean breaking strength

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.02 < t_4_4 < 2.02) = 0.95  {As the critical value of t at 44 degree

                                           of freedom are -2.02 & 2.02 with P = 2.5%}  

P(-2.02 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.02) = 0.95

P( -2.02 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.02 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.02 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.02 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.02 \times {\frac{s}{\sqrt{n} } } , \bar X+2.02 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 768.2-2.02 \times {\frac{15.1}{\sqrt{45} } } , 768.2+2.02 \times {\frac{15.1}{\sqrt{45} } } ]

                                     = [763.65 lb , 772.75 lb]

Therefore, 95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

3 0
3 years ago
Due this Thursday.. help pls.​
ra1l [238]

9514 1404 393

Answer:

  9.90×10^-15

Step-by-step explanation:

The leading non-zero digit must be move 15 places to the left to put it in the units place. Having done that, its original value will be restored by multiplying by 10^-15.

Rounded to 3 significant figures, 989912345 becomes 990. The trailing zero must be kept as part of the number to indicate that there are 3 significant figures.

In scientific notation, the number is ...

  9.90×10^-15

_____

<em>Additional comment</em>

If the number can be copied and pasted to a spreadsheet, it can be formatted to scientific notation with the required number of digits. Here, we can't copy the number from the image, so we have marked off the decimal places in a way that makes them easier to count. Copying the given number text would avoid any transcription errors.

8 0
2 years ago
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