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3 years ago

Root99 + root44 can someone help?

Mathematics

1 answer:

iogann1982 [59]3 years ago

6 0

Answer:

here I worked it out on my calculator so it should be right

5 root 11

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It is 90 ft between the bases of baseball diamond. A catcher throws a baseball to the shortstop who is half-way between second a

Hunter-Best [27]

Answer:

127.3 ft

Step-by-step explanation:

A baseball diamond is constructed in a square shape.

The sides are 90 ft each

If a catcher throws a baseball to the shortstop who is half-way between second and third bases, the distance between the third base and the short stop = 1/2(90)

= 45 ft

length of the throw is found using Pythagoras theorem.

Hypothenus ^2 = opposite ^2 + adjacent ^2

= 90^2 + 45^2

Hypothenus = √8100 + 2025

=√10125

= 100.62 ft (approximately)

8 0

3 years ago

2x3 equals what because I didn’t get it

SashulF [63]

Ok so 2x3= 6 so yeah

8 0

3 years ago

Read 2 more answers

If sin 150° is 1/2 find sin75°

lisabon 2012 [21]

Answer:

use a calculator and enter those numbers then press SIN

Step-by-step explanation:

7 0

3 years ago

Angle α lies in quadrant II , and tanα=−125 . Angle β lies in quadrant IV , and cosβ=35 .

Artist 52 [7]

Answer:

$cos(\alpha+\beta)=\frac{33}{65}$

Step-by-step explanation:

step 1

Find cos α

we know that

$tan^2(\alpha)+1=sec^2(\alpha)$

we have

$tan(\alpha)=-\frac{12}{5}$

substitute

$(-\frac{12}{5})^2+1=sec^2(\alpha)$

$sec^2(\alpha)=\frac{144}{25}+1$

$sec^2(\alpha)=\frac{169}{25}$

$sec(\alpha)=\pm\frac{13}{5}$

Remember that Angle α lies in quadrant II

sec α is negative

$sec(\alpha)=-\frac{13}{5}$

Find the value of cos α

$cos)\alpha)=\frac{1}{sec(\alpha)}$

$cos(\alpha)=-\frac{5}{13}$

step 2

Find sin α

we know that

$tan(\alpha)=\frac{sin(\alpha)}{cos(\alpha)}$

$sin(\alpha)=tan(\alpha)cos(\alpha)$

we have

$tan(\alpha)=-\frac{12}{5}$

$cos(\alpha)=-\frac{5}{13}$

substitute

$sin(\alpha)=(-\frac{12}{5})(-\frac{5}{13})$

$sin(\alpha)=\frac{12}{13}$

step 3

Find sin β

we know that

$sin^2(\beta)+cos^2(\beta)=1$

we have

$cos(\beta)=\frac{3}{5}$

substitute

$sin^2(\beta)+(\frac{3}{5})^2=1$

$sin^2(\beta)=1-(\frac{3}{5})^2$

$sin^2(\beta)=1-\frac{9}{25}$

$sin^2(\beta)=\frac{16}{25}$

$sin(\beta)=\pm\frac{4}{5}$

Remember that

Angle β lies in quadrant IV

sin β is negative

$sin(\beta)=-\frac{4}{5}$

step 4

Find cos(α−β)

we know that

$cos(\alpha+\beta)=cos(\alpha)cos(\beta)-sin(\alpha)sin(\beta)$

we have

$cos(\alpha)=-\frac{5}{13}$

$cos(\beta)=\frac{3}{5}$

$sin(\alpha)=\frac{12}{13}$

$sin(\beta)=-\frac{4}{5}$

substitute the given values

$cos(\alpha+\beta)=(-\frac{5}{13})(\frac{3}{5})-(\frac{12}{13})(-\frac{4}{5})$

$cos(\alpha+\beta)=(-\frac{15}{65})+(\frac{48}{65})$

$cos(\alpha+\beta)=\frac{33}{65}$

7 0

4 years ago

Xavier made 25 pounds of roasted almonds for a fair he has 3 and 1/2 pounds left at the end of the fair how many pounds of roast

Pepsi [2]

Answer:

Step-by-step explanation:

25-x=3 (1/2)

you just subtract 25 by 3 (1/2), and you get 21 (1/2).

Xavier sold 21 (1/2) pounds of roasted almonds

4 0

3 years ago