Question

Solve the problem and then click on the correct graph. |x| + y ≥ 0

Answer 1

Given that |x| + y ≥ 0, this means that y ≥ -|x|

Because |x| is always positive, then -|x| will always be negative.

The correct graph is the second graph.

Answer 2

Answer with explanation:

The given Inequality is

 | x |+ y ≥ 0

As, |x|=x,when ,x ≥ 0

and ,|x|= -x,when , x<0.

So,inequality reduces to

1.→x + y ≥ 0, when , x ≥ 0.

2.→-x + y ≤ 0,when , x≥y and , x<0.

And,3.→ -x + y ≥ 0,when , x ≤ y and , x<0.

So, these are three equation for which we have to draw the graph.which i am writing again as we have to draw the graph of these equation

1. x+y ≥0, x≥ y and,x ≥ -y,x≥0.

2. - x + y ≤ 0, when , x ≥ y,and x<0.

3. -x + y ≥0,when , x≤y and x<0.

Option B