Answer:
e. It will take 11 seconds to reach the maximum height of 1,936 feet.
f. It will take 22 seconds to return to the earth.
Step-by-step explanation:
Given:
Initial velocity
= 352 ft/sec
Solving for question e.
To find the time required to reach the maximum height we will use the formula,
,
where
is the starting velocity
is the initial height.
Using the velocity and starting height from our problem we have,
,
The path of this rocket will be a downward facing parabola, so there will be a maximum.
This maximum will be at the vertex of the graph.
To find the vertex we start out with
which in our case is,
![x=\frac{-352}{2(-16)}=\frac{-352}{-32}= 11](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-352%7D%7B2%28-16%29%7D%3D%5Cfrac%7B-352%7D%7B-32%7D%3D%2011)
So, It will take 11 seconds for the rocket to reach its maximum height.
We will find maximum height using the formula by substituting value of t we get,
![h(11)=-16(11^2)+352(11)+0\\h(11) = -16 \times121+ 352 \times 11 = -1936+3872= 1936 \ ft](https://tex.z-dn.net/?f=h%2811%29%3D-16%2811%5E2%29%2B352%2811%29%2B0%5C%5Ch%2811%29%20%3D%20-16%20%5Ctimes121%2B%20352%20%5Ctimes%2011%20%3D%20-1936%2B3872%3D%201936%20%5C%20ft)
Hence the maximum height will be ![1936 \ ft](https://tex.z-dn.net/?f=%201936%20%5C%20ft)
Now Solving for question f.
To find the time required for rocket to reach earth.
We will set our formula to 0 to find the time.
![0= -16t^2+352t+0\\-16t(t-22)=0](https://tex.z-dn.net/?f=0%3D%20-16t%5E2%2B352t%2B0%5C%5C-16t%28t-22%29%3D0)
Using the zero product property, we know that either -16t = 0 or t - 22 = 0. When -16t = 0 is at t = 0, when the rocket is launched. t - 22 = 0 gives us an answer of t = 22.
So the rocket reaches the Earth again at 22 seconds.