Question

How much heat is added if .7892g of water is increased in temperature by .039 degrees C?

Answer 1

Answer:

=0.1293 J

Explanation:

The heat increase is the change in energy for the water ΔH.

ΔH=MC∅ where M is mass, C is the specific heat capacity for water and ∅ is the change in temperature.

M=0.7892g

C(for water) =4.2 J/g°C

∅=0.039 °C

ΔH=0.7892g×4.2 J/g°C×0.039°C

=0.1293 J

The amount of heat energy added to cause the 0.039°C temperature increase is 0.1293 Joules.