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4 years ago

10

Why did Rutherford conclude that the atom was mostly empty space?

1 answer:

olga nikolaevna [1]4 years ago

6 0

Rutherford came to this conclusion after his Gold-Foil experiment. He found that most of the alpha particales(when released) went straight through the gold foil, of which consisted of atoms. In the middle of the atom theres a small nucleus that has mass and positive charge. Because the nucleus is so small the alpha <span>particles were able to go straight through leading to the conclusion that atoms are mostly empty space. </span>

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help!!!! the relative formula mass (Mr) of sodium fluoride is 42. Use the correct answer frim the box to complete the sentence.

arsen [322]

Answer:

mole

Explanation:

Since Sodium Chloride is ionic, it cannot be considered a molecule as per the definition of a molecule requires each of its components to be bonded together.

3 0

2 years ago

If 1.8 L of water is added to 2.5L of a 7.0 M KOH solution, what is the molarity of the new solution

tatyana61 [14]

Answer : The molarity of the new solution is, 4.069 M

Solution : Given,

Molarity of KOH solution = 4 M

Volume of KOH solution = 2.5 L

Volume of water added = 1.8 L

First we have to calculate the volume of new solution.

Volume of new solution = volume of KOH solution + volume of water added

Volume of new solution = 2.5 L + 1.8 L = 4.3 L

Now we have to calculate the molarity of the new solution.

Formula used :

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of KOH solution

$M_2$ = molarity of new solution

$V_1$ = volume of KOH solution

$V_2$ = volume of new solution

Now put all the given values in the above formula, we get the molarity of the new solution.

$(7M)\times (2.5L)=M_2\times (4.3L)$

$M_2=4.069M$

Therefore, the molarity of the new solution is, 4.069 M

3 0

4 years ago

What is the critical angle for the interface between water and diamond?

Evgesh-ka [11]

Answer:

33 degrees

Explanation:

The critical angle for a light ray moving from a denser medium with refractive index $n_1$ to a second medium with refractive index $n_2$ is given by

$\theta_c = sin^{-1} (\frac{n_2}{n_1})$

In this case, the critical angle occurs when light moves from diamond to water. The index of refraction of the two materials are:

$n_d = 2.42$ for diamond

$n_w = 1.33$ for water

So the critical angle is

$\theta_c = sin^{-1} (\frac{1.33}{2.42})=sin^{-1}(0.550)=33.3^{\circ}$

5 0

3 years ago

What else is produced during the replacement reaction of magnesium and hydrochloric acid?

sweet [91]

It's a single- replacement reaction so Mg+ 2HCl ➡️ H2+ MgCl2

5 0

3 years ago

Read 2 more answers

What volume of hydrogen gas is required to react with 113 liters of ethylene (C2H4) according to the following reaction? (All ga

AysviL [449]

<u>Answer:</u> The volume of hydrogen gas required for the given amount of ethylene gas is 113 L

<u>Explanation:</u>

At STP:

1 mole of a gas occupies 22.4 L of volume

We are given:

Volume of ethylene = 113 L

For the given chemical equation:

$H_2(g)+C_2H_4(g)\rightarrow C_2H_6(g)$

By Stoichiometry of the reaction:

$(1\times 22.4)L$ of ethylene reacts with $(1\times 22.4)L$ of hydrogen gas

So, 113 L of ethylene gas will react with = $\frac{(1\times 22.4)}{(1\times 22.4)}\times 113=113L$ of hydrogen gas

Hence, the volume of hydrogen gas required for the given amount of ethylene gas is 113 L

5 0

3 years ago