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Leno4ka [110]
3 years ago
10

Calculate the pH of 0.50M H2S

Chemistry
1 answer:
-BARSIC- [3]3 years ago
5 0
I got that pH=3.65 using the fact that Ka=[H⁺][A⁻]/[HA] at equilibrium.  In the ice table, I stands for initial, C stands for change, and E stands for equilibrium.  

I hope this helps.  Let me know if anything is unclear.

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The forensic technician at a crime scene has just prepared a luminol stock solution by adding 18.0 g of luminol to H2O creating
Bond [772]

Answer:

Part A. 1.355 mol/L

Part B. 0.100 mol

Part C. 74.0 mL

Explanation:

Part A.

The molar mass of luminol is 177.16 g/mol, so the number of moles at 18.0 g is:

n = mass/molar mass

n = 18.0/177.16

n = 0.1016 mol

The molarity is the number of moles divided by the volume (0.075 L)

C = 0.1016/0.075

C = 1.355 mol/L

Part B.

The number of moles is the molarity multiplied by the volume, so:

n = 5.00x10⁻² mol/L * 2.00 L

n = 0.100 mol

Part C.

To prepare a solution by dilution, we can use the equation

C1V1 = C2V2

Where C1 is the concentration of the initial (stock) solution, V1 is its volume necessary, C2 is the concentration of the diluted solution, and V2 is its volume.

Thus, C1 = 1.355 M, C2 = 0.05 M, V2 = 2.00 L

1.355V1 = 0.05*2

V1 = 0.074 L

V1 = 74.0 mL

6 0
3 years ago
What happens to traits when mutations happen
Wittaler [7]
Physical or mental traits change
7 0
3 years ago
Show
SIZIF [17.4K]

Answer: 0.9375 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}     .....(1)

Molarity of HCl solution = 0.75 M

Volume of HCl solution = 25.0 mL = 0.025 L

Putting values in equation 1, we get:

\text{Moles of} HCl={0.75}\times{0.025}=0.01875moles  

CaCO_3(s)+2HCl(aq)\rightarrow CaCl_2(s)+CO_2(g)+H_2O(l)  

According to stoichiometry :

2 moles of HCl require = 1 mole of CaCO_3

Thus 0.01875 moles of HCl will require=\frac{1}{2}\times 0.01875=0.009375moles  of CaCO_3

Mass of CaCO_3=moles\times {\text {Molar mass}}=0.009375moles\times 100g/mol=0.9375g

Thus 0.9375 g of CaCO_3 is required to react with 25.0 ml of 0.75 M HCl

6 0
3 years ago
Fill in the blanks. The celestial bodies in space move about in predictable paths called
ella [17]

Answer:

Magnetic fields, revolve, asteroids

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3 years ago
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4. Describe the water conditions in the latitudes where coral reefs are found.<br> Help
Fofino [41]

Answer:

  • Most coral reefs lie between the latitudes of 30 degrees north and south where sea temperatures are warmest.
  • it is generally present in tropical and semi-tropical waters.
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