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olasank [31]
4 years ago
9

The statemment 3+3=6 serves as a/an ___ to the conjecture that the sum of two odd numbers is an odd number.

Mathematics
1 answer:
s344n2d4d5 [400]4 years ago
7 0
<span>The statement 3+3=6 serves as a disproof to the conjecture that the sum of two odd numbers is an odd number.
Odd numbers are numbers which can </span><span> NOT be divided evenly into groups of </span>two<span>.
6 can be divided by 2 (6:3=2), which means that the sum of two odd numbers is not an odd number. 
</span>On the other hand, there is a statement that is always true (a theorem) about the sum of two odd numbers: <span>The sum of two consecutive odd numbers is </span>divisible<span> by 4. </span>
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What are the solutions to the quadratic equation (5y+6)2=24
yulyashka [42]

The value of y is, y=\frac{2\sqrt{6}-6}{5},\:y=\frac{-2\sqrt{6}-6}{5}

We have given that,

\left(5y+6\right)^2=24

We have to determine the value of y,

<h3>What is the formula for the quadratic equation?</h3>

\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

Therefore,we get

5y+6=\sqrt{24}

5y+6=2\sqrt{6}

\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}

5y+6-6=2\sqrt{6}-6

5y=2\sqrt{6}-6

\frac{5y}{5}=\frac{2\sqrt{6}}{5}-\frac{6}{5}

y=\frac{2\sqrt{6}-6}{5}

y=\frac{2\sqrt{6}-6}{5},\:y=\frac{-2\sqrt{6}-6}{5}

Therefore the value of y is,

y=\frac{2\sqrt{6}-6}{5},\:y=\frac{-2\sqrt{6}-6}{5}

To learn more about the quadratic equation visit:

brainly.com/question/1214333

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2 years ago
How do you write 100 as a power of ten
stealth61 [152]
The answer is to that is 10² because 10small one equals 10 and 10³ equals 1000 and you going on my multiplying it by 1ofoe example 100*10 equals 1000.


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3 years ago
Which one is bigger, 80 centimeters or 19 millimeters?
kondor19780726 [428]
80 centimeters by far
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3 years ago
Scores of an IQ test have a​ bell-shaped distribution with a mean of and a standard deviation of . Use the empirical rule to det
Oduvanchick [21]

Complete question is;

Scores of an IQ test have a​ bell-shaped distribution with a mean of 100 and a standard deviation of 13. Use the empirical rule to determine the following.

​(a) What percentage of people has an IQ score between 87 and 113​?

​(b) What percentage of people has an IQ score less than 74 or greater than 126​? ​

(c) What percentage of people has an IQ score greater than 139​?

Answer:

A) 68% of the people had an IQ score between 87 and 113

B) 5% of the people had IQ scores less than 74 and greater than 126.

C) 0.15% had an IQ score greater than 139

Step-by-step explanation:

We are given;

Mean; x¯ = 100

Standard deviation; σ = 13

According to the empirical rule in statistics;

>> 68% of the data lies within one standard deviation of the mean

>> 95% of the data lies within two standard deviations of the mean

>> 99.7% of the data lies within three standard deviations

A) We want to find the percentage of people with an IQ score between 87 and 113.

Within one standard deviation, we have;

x¯ ± σ

>> (100 - 13), (100 + 13)

>> (87, 113) which is the range we are looking for.

Thus, 68% of the people had an IQ score between 87 and 113

B) we want to find percentage of people has an IQ score less than 74 or greater than 126.

Let's first find those who had between 74 and 126.

Let's use two standard deviations within the mean.

x¯ ± 2σ

>> (100 - (2×13)), (100 + (2×13))

>> (74, 126) which is the range we are looking for.

So percentage that have IQ scores between 74 and 126 is 95%

Thus;

Percentage of those who had less than 74 and greater than 126 is;

P = 1 - 95%

P = 5%

C) we want to find the percentage of people that had an IQ score greater than 139.

Let's use the z-score formula;

z = (x¯ - μ)/σ

z = (139 - 100)/13

z = 39/13

z = 3

This means it is 3 standard deviations above the mean.

Thus;

Since it's one side outside the mean, then;

Percentage of people with an IQ score greater than 139 = (1 - 99.7%)/2 = 0.3%/2 = 0.15%

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Answer:

20 weeks in 1 week

in 2 weeks 40

Step-by-step explanation:

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