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AlladinOne [14]
3 years ago
6

Please help!!!! 6x + 3 = ?? when x = 5?? Thanks in advance!!!!!!!!!

Mathematics
2 answers:
MrMuchimi3 years ago
7 0
33 because 6x5=30 then plus 3 equals 33
9966 [12]3 years ago
6 0
Hey there!

So we do know the value of x (x = 5)

6 * 5 = 30

Now add the numbers 30 and 3 . . .

30 + 3 = 33

The answer to your question is 33.

Hope this helps you.
Have a great day!
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What is the simplified form of the expressions?<br> a. −6a2b−1 <br> b. 5/y−3
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Answer:

a.

-6a²/ b

b.

5y³

Step-by-step explanation:

a

-6a²b⁻¹

-6a²/ b

b.

5/ y⁻³

5 / 1/ y³

5 * y³/1

5y³

8 0
4 years ago
classify the equation 6(x + 2) = 5(x + 7) as having one solution, no solution, or infinitely many solutions
FromTheMoon [43]

Answer:

Step-by-step explanation:

The equation has one solution.

6(x+2)=5(x+7)

6x+12=5x+35

6x+12-5x=35

6x-5x=35-12

x=23

Therefore, the equation has ONE solution.

7 0
3 years ago
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X is 9 Y is 3 and Z is 12
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Write an expression that represents the width of a rectangle with length x+5 and area x^3+12x^2+47x+60
xeze [42]
Area divided by length= width
x^3+12x^2+47x+60 ÷ x+5=w
6 0
3 years ago
Find the distance between (-5,6)and (3,2).
skad [1K]

Answer:

\displaystyle d = 4\sqrt{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formulas]:                                                     \displaystyle d = \sqrt{(3+5)^2+(2-6)^2}
  2. [Distance] [√Radical] (Parenthesis) Add/Subtract:                                       \displaystyle d = \sqrt{(8)^2+(-4)^2}
  3. [Distance] [√Radical] Evaluate exponents:                                                    \displaystyle d = \sqrt{64+16}
  4. [Distance] [√Radical] Add:                                                                             \displaystyle d = \sqrt{80}
  5. [Distance] [√Radical] Simplify:                                                                         \displaystyle d = 4\sqrt{5}
6 0
3 years ago
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