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Anna71 [15]
3 years ago
11

Write an expression that represents the width of a rectangle with length x+5 and area x^3+12x^2+47x+60

Mathematics
1 answer:
xeze [42]3 years ago
6 0
Area divided by length= width
x^3+12x^2+47x+60 ÷ x+5=w
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I NEED THE ANSWER RIGHT NOW PLEASE!!!
strojnjashka [21]

Answer:

Second : 1/6 x + 47

Third : 1 2/3 x + 35 - 1 1/2 x + 12

Fourth : 5 (1/3x) + (5) (7) - (3) (1/2x) + (3) (4)

Step-by-step explanation:

I would start by expanding the expression, showing each step. Then, simplify by collecting like terms.

To expand, you multiply the term outside of the brackets by each term inside the brackets.

5(1/3x + 7) - 3(1/2x - 4)

= 5(1/3x) + (5)(7) - (3)(1/2x) + (3)(4)       Showing how to expand

= 5/3x + 35 - 3/2x + 12           Simplified above step by multiplying

= 5/3x - 3/2x + 47            Collected like terms (35 + 12 = 47)

= 10/6x - 9/6x + 47          Change fractions to the common denominator 6

= \frac{10-9}{6}x + 47   Combine fractions with common denominator

= 1/6x + 47              Fully expanded

See which options match the steps I took to expand the original expression.

The second step is the same as option 4.

The last step is the same as option 2.

I bolded those steps that are the same.

Some options use mixed fractions (whole numbers and fractions).

From the third step, I will convert the improper fractions to mixed fractions.

5/3x + 35 - 3/2x + 12

= 1 2/3x + 35 - 1 1/2x + 12

This is the same as option 3.

\frac{5}{3}x = 1\frac{2}{3}x    On the left side, 5 goes into 3 ONE time. The ONE becomes the whole number. After 5 goes into 3, there is 2 left, which becomes the numerator.

\frac{3}{2}x = 1\frac{1}{2}x   On the left side, 3 goes into 2 ONE time. The ONE becomes the whole number. The remainder is 1, which becomes the numerator.

6 0
3 years ago
Read 2 more answers
On 1st January 2020, Laurie invests P dollars in an account that pays a nominal annual interest rate of 5.5%, compounded quarter
andrezito [222]

Answer:

1) The common ratio =  1.055

2) The year in which the amount of money in Laurie's account will become double is the year 2032

Step-by-step explanation:

1) The given information are;

The date Laurie made the investment = 1st, January, 2020

The annual interest rate of the investment = 5.5%

Type of interest rate = Compound interest

Therefore, we have;

The value, amount, of the investment after a given number of year, given as follows;

Amount in her account = a, a × (1 + i), a × (1 + i)², a × (1 + i)³, a × (1 + i)ⁿ

Which is in the form of the sum of a geometric progression, Sₙ given as follows;

Sₙ = a + a × r + a × r² + a × r³ + ... + a × rⁿ

Where;

n = The number of years

Therefore, the common ratio = 1 + i = r = 1 + 0.055 = 1.055

The common ratio =  1.055

2) When the money doubles, we have;

2·a = a × rⁿ = a × 1.055ⁿ

2·a = a × 1.055ⁿ

2·a/a = 2 = 1.055ⁿ

2 = 1.055ⁿ

Taking log of both sides gives;

㏒2 = ㏒(1.055ⁿ) = n × ㏒(1.055)

㏒2 = n × ㏒(1.055)

n = ㏒2/(㏒(1.055)) ≈ 12.95

The number of years it will take for the amount of money in Laurie's account to double = n = 12.95 years

Therefore, the year in which the amount of money in Laurie's account will become double = 2020 + 12..95 = 2032.95 which is the year 2032

The year in which the amount of money in Laurie's account will become double = year 2032.

3 0
3 years ago
Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court
Ksju [112]

Answer:

(a)\dfrac{92}{117}

(b)\dfrac{8}{39}

(c)\dfrac{25}{117}

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed)=P(MW)+P(WM)

=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.
  • Two women are appointed

P(at least one woman is appointed)=P(MW)+P(WM)+P(WW)

P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}

In Part B, P(MW)+P(WM)=\frac{8}{39}

Therefore:

P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}

5 0
3 years ago
Whta is the answer to the multiplication problem below? Look at the graph in picture
just olya [345]

Answer:

3/4

Step-by-step explanation:

6 squares of 8 which can be simplified to 3/4

5 0
3 years ago
How do I find side b?
stiv31 [10]

Answer:

u use cosine

and then some proportion

i am 60% sure

dont trust me

i learned this a week ago and now i forget it all help me study for the quiz i have on this tmrw?

8 0
3 years ago
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