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Svetlanka [38]
2 years ago
10

Jake is skipping stones onto a pond. Each time he flings a stone in, he counts

Mathematics
2 answers:
Rasek [7]2 years ago
6 0
You should use the mean which is the average of all the numbers
Ulleksa [173]2 years ago
3 0

<u>Answer:</u>

B. mode

<u>Step-by-step explanation:</u>

We are given the following data set for the number of skips every time Jake skipped a stone onto a pond:

3, 2, 1, 3, 2, 5, 4, 1, 3, 3, 4, 1, 5, 4, 2

It is a good idea to arrange the data set into ascending order just to be more clear about it:

1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5

To find the most common number of skips, Jake should use a measure called mode which tells us about the value that appears most often, which in this case is 3.


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Avery has 125 animal stickers. She gave 5 animal stickers to each of her 10 friends. HoW many animal stickers she have left? Wha
Angelina_Jolie [31]

Answer:

75

Step-by-step explanation:

125-(5*10)        

125-(50)

75

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(01.03 MC) Traveling at 65 miles per hour, how many minutes, rounded to the nearest whole number, does it take to drive 125 mile
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It should take 115 minutes
4 0
2 years ago
2a) Solve using substitution.
Tcecarenko [31]
First things first, write out your equation without the substitution.

2x+ 2y= 10

Now, put in the substitution.

2x+ 2• 2= 10

Combine like terms.

2x+ 4= 10

Now that your equation it simplified, you need to reverse the problem and put everything on the other side.

2x+ 4= 10
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2x=6
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2 2

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So the final answer is x=3

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Step-by-step explanation:

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7 0
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Suppose the total area is represented by the equation x^2+14x+24. If the area 1 is x^2 square units and area IV is 24 units, wha
Nutka1998 [239]

Answer:

See Explanation

Step-by-step explanation:

Given

Total = x^2 + 14x + 24

Area\ I = x^2

Area\ IV = 24

Required

True about area II and III

The question is incomplete; so, I will answer using general knowledge.

If the total area is:

Total = x^2 + 14x + 24

And there are 4 areas, then;

Total = Area\ I + Area\ II + Area\ III + Area\ IV

Rewrite as:

Total = Area\ I + Area\ IV+ Area\ II + Area\ III

This gives:

x^2 + 14x + 24 = x^2 + 24+ Area\ II + Area\ III

Collect like terms

x^2 -x^2 + 14x + 24 -24=  Area\ II + Area\ III

14x =  Area\ II + Area\ III

Rewrite as:

Area\ II + Area\ III  = 14x

<em>So, the sum of areas III and IV must be 14x</em>

4 0
3 years ago
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