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Svetlanka [38]
3 years ago
10

Jake is skipping stones onto a pond. Each time he flings a stone in, he counts

Mathematics
2 answers:
Rasek [7]3 years ago
6 0
You should use the mean which is the average of all the numbers
Ulleksa [173]3 years ago
3 0

<u>Answer:</u>

B. mode

<u>Step-by-step explanation:</u>

We are given the following data set for the number of skips every time Jake skipped a stone onto a pond:

3, 2, 1, 3, 2, 5, 4, 1, 3, 3, 4, 1, 5, 4, 2

It is a good idea to arrange the data set into ascending order just to be more clear about it:

1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5

To find the most common number of skips, Jake should use a measure called mode which tells us about the value that appears most often, which in this case is 3.


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RSM wants to send four of its 18 Math Challenge teachers to a conference. How many combinations of four teachers include exactly
tatiyna

Answer:

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

Step-by-step explanation:

The order in which the teachers are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

1 from a set of 2(Either Mrs. Vera or Mr. Jan).

3 from a set of 18 - 2 = 16. So

C_{2,1}C_{16,3} = \frac{2!}{1!1!} \times \frac{16!}{3!13!} = 1120

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

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3 years ago
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Answer:

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Akimi4 [234]

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Step-by-step explanation:

For problems like these I take the largest number in this case 10, and start writing out what 2 numbers would give me 10. 0+10, 1+9, 2+8, 3+7...while doing that I subtract the numbers as well. thus 3+7=10 3-7=-4

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