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ivann1987 [24]
3 years ago
11

What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation is y=−23x+5

?
Mathematics
1 answer:
elena-s [515]3 years ago
5 0

Answer:

y-1=\frac{1}{23} (x-8)

Step-by-step explanation:

We can write the equation of a line in 3 different forms including slope intercept, point-slope, and standard depending on the information we have. We have a point (8,1) and a slope from the equation y=-23x+5. We will chose point-slope since we have a point and slope.

Point slope:y-y_1=m(x-x_1)

m\neq -23 in our new equation because it us perpendicular to it. This means we will need to change it into its negative reciprocal which is m=\frac{1}{23}.

We will substitute m=\frac{1}{23} and x_1=8\\y_1=1.

y-1=\frac{1}{23} (x-8).

This is the equation of the line perpendicular to y=-23x+5 that crosses through (8,1).



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