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sergejj [24]
3 years ago
9

This got me confused please help

Mathematics
1 answer:
Sever21 [200]3 years ago
5 0
Me too lol anyway thanks for the free points ig
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Pls answer these questions for me pls and thanks
ivann1987 [24]

Answer:

16= 4²

25= 5²

36= 6²

49= 7²

64= 8²

81= 9²

so, third option is correct I.e. 49

hope it will help....

3 0
3 years ago
What is the function rule of the line parallel to y = 2x + 7 that passes through the point (-3,5)?
kykrilka [37]

Answer:

y = 2x + 11

Step-by-step explanation:

Parallel means the two lines have the same slope. The slope = 2 because the two is in front of the x. Whatever number is in front of the x is the slope.

So far what you know is

y = 2x + b

The point (-3,5) is what you need to get b.

y = 2x + b

y = 5

x = - 3

5 = -3(2) + b

5 = -6 + b

b = 5 + 6

b = 11

============

Equation

y = 2x + 11

6 0
3 years ago
WILL GIVE ALL 5 AND BRAINLIEST
zheka24 [161]

Answer:

Top to bottom

less

less

greater

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
( 15 points and brainliest) The volume of a tighter cylinder is 87.92 cm ^3 (that means cubed, or to the 3rd power). The radius
blsea [12.9K]
Given that:
Volume of cylinder, V= 87.92 cm³
Radius, r= 2 cm
π=3.14
Formula for volume of cylinder:
V=πr²h
Put values in the formula.
87.92=(3.14)(2)²h
87.92=(3.14)(4)h
87.92=12.56h
Divide both sides by 12.56
7=h
or
h=7 cm

Answer: Height of Cylinder is 7 cm.


6 0
4 years ago
An engineer is planning a new water pipe installation. The circular pipe has a diameter of d=20\text{ cm}d=20 cmd, equals, 20, s
aivan3 [116]

Answer: The answer is 314.28 cm² (approx.).


Step-by-step explanation:  Given that an engineer is going to install a new water pipe. The diameter of this circular pipe is, d = 20 cm.

We need to find the area 'A' of the circular cross-section of the pipe.

Given, diameter of the circular section is

\textup{d}=20~\textup{cm}.

So, the radius of the circular cross-section will be

\textup{r}=\dfrac{\textup{d}}{2}=\dfrac{20}{2}=10~\textup{cm}.

Therefore, cross-sectional area of the pipe is

\textup{A}=\pi \textup{r}^2=\dfrac{22}{7}(10)^2=\dfrac{2200}{7}=314\dfrac{2}{7}=314.28~.~.~.~\textup{cm}^2.

Thus, the answer is 314.28 cm² (approx.).

4 0
4 years ago
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