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3 years ago

A certain medicine is given in an amount proportional to a patient's body weight. Suppose a patient weighing

1 answer:

6 0

Set up a proportion.

pounds / milligrams of medicine

195/279 = 130/x

195x = 279 times 130
195x =36,270
x = 36,270/195
x = 186

A patient weighing 130 pounds needs 186 milligrams of medicine.

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Solve the equation below for x by graphing. x ≈ -2.50 x ≈ 2.50 x ≈ -0.50 x ≈ -6.00

Sunny_sXe [5.5K]

Where is the graph??

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4 years ago

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What is equivalent to 2/5?

zhuklara [117]

As in decimal it would be 0.4 but if you want a fraction it could be 4/10

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3 years ago

$800 and paid 14% tax what was final bill

evablogger [386]

Answer:

$912

Step-by-step explanation:

First, find the tax.

Multiply the tax rate by the price.

tax rate * price

The tax rate is 14% and the price is $800.

14% * 800

Convert 14% to a decimal. Divide 14 by 100 or move the decimal places 2 spaces to the left.

14/100=0.14

14.0–> 1.4 —> 0.14

0.14 * 800

Multiply

112

The tax is $112.

Now find the total bill.

Add the tax and the price.

tax + price

The tax is $112 and the price is $800.

$112 + $800

Add

$912

The final bill is $912.

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3 years ago

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The spinner has eight spaces of equal size. What is the mathematical probability of the pointer's stopping in the space marked 1

Advocard [28]

Answer:

10/40

Step-by-step explanation:

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3 years ago

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Which of the following equations represents the perpendicular bisector of WX graphed below?

kotykmax [81]

The coordinates of the 2 given points are W(-5, 2), and X(5, -4).

First, we find the midpoint M using the midpoint formula:

$\displaystyle{ M_{WX}= (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )= (\frac{-5+5}{2}, \frac{2+(-4)}{2} )=(0, -1).$

Nex, we find the slope of the line containing M, perpendicular to WX. We know that if m and n are the slopes of 2 parallel lines, then mn=-1.

The slope of WX is $\displaystyle{ m= \frac{y_2-y_1}{x_2-x_1}= \frac{2-(-4)}{-5-5}= \frac{6}{-10}= -\frac{3}{5}$ .

Thus, the slope n of the perpendicular line is $\displaystyle{ \frac{5}{3}$ .

The equation of the line with slope $\displaystyle{ n= \frac{5}{3}$ containing the point M(0, -1) is given by:

$\displaystyle{ y-(-1)=\frac{5}{3}(x-0)$

$\displaystyle{ y+1= \frac{5}{3}x$

$\displaystyle{ 3y+3=5x$

$\displaystyle{ 5x-3y-3=0$

Answer: 5x-3y-3=0

8 0

3 years ago