The answer is b hopefully I helped
Answer:
The range of T is a subspace of W.
Step-by-step explanation:
we have T:V→W
This is a linear transformation from V to W
we are required to prove that the range of T is a subspace of W
0 is a vector in range , u and v are two vectors in range T
T = T(V) = {T(v)║v∈V}
{w∈W≡v∈V such that T(w) = V}
T(0) = T(0ⁿ)
0 is Zero in V
0ⁿ is zero vector in W
T(V) is not an empty subset of W
w₁, w₂ ∈ T(v)
(v₁, v₂ ∈V)
from here we have that
T(v₁) = w₁
T(v₂) = w₂
t(v₁) + t(v₂) = w₁+w₂
v₁,v₂∈V
v₁+v₂∈V
with a scalar ∝
T(∝v) = ∝T(v)
such that
T(∝v) ∈T(v)
so we have that T(v) is a subspace of W. The range of T is a subspace of W.
Answer:
The correct option is 1.
Step-by-step explanation:
If a quadratic equation is defined as
.... (1)
Then the sum of the roots is -b/a and the product of roots is c/a.
The given equation is
... (2)
From (1) and (2) we get a=3, b=11 and c=-4.
The sum of roots is
The sum of roots is 
.
Therefore the correct option is 1.
Answer: a rectangular prism
Step-by-step explanation:
Tom bought 768 pounds of candy because 333 + 435 = 768
