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tigry1 [53]
3 years ago
12

Simplify 2x2 - y for x= 3 and y=-2.

Mathematics
1 answer:
amm18123 years ago
7 0

Answer:

<u>14</u>

Step-by-step explanation:

Plug and chug

<em>2</em>

<em>8*(3)*2 - (-2) </em>

12 - (-2)

14

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Find the sum of -10x^2-x+6−10x 2 −x+6 and 10x^2-510x 2 −5.
irina [24]

Answer:

1. -10x^2-x+6-10x 2-x+6 = -10x^2 - 22x + 12

2. 10x^2-510x 2-5 = 10x^2 - 1020x - 5

Step-by-step explanation:

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DIscrete Math
Daniel [21]

Answer:

Step-by-step explanation:

As the statement is ‘‘if and only if’’ we need to prove two implications

  1. f : X \rightarrow Y is surjective implies there exists a function h : Y \rightarrow X such that  f\circ h = 1_Y.
  2. If there exists a function h : Y \rightarrow X such that  f\circ h = 1_Y, then f : X \rightarrow Y is surjective

Let us start by the first implication.

Our hypothesis is that the function f : X \rightarrow Y is surjective. From this we know that for every y\in Y there exist, at least, one x\in X such that y=f(x).

Now, define the sets X_y = \{x\in X: y=f(x)\}. Notice that the set X_y is the pre-image of the element y. Also, from the fact that f is a function we deduce that X_{y_1}\cap X_{y_2}=\emptyset, and because  f the sets X_y are no empty.

From each set X_y  choose only one element x_y, and notice that f(x_y)=y.

So, we can define the function h:Y\rightarrow X as h(y)=x_y. It is no difficult to conclude that f\circ h(y) = f(x_y)=y. With this we have that f\circ h=1_Y, and the prove is complete.

Now, let us prove the second implication.

We have that there exists a function  h:Y\rightarrow X  such that f\circ h=1_Y.

Take an element y\in Y, then f\circ h(y)=y. Now, write x=h(y) and notice that x\in X. Also, with this we have that f(x)=y.

So, for every element y\in Y we have found that an element x\in X (recall that x=h(y)) such that y=f(x), which is equivalent to the fact that f is surjective. Therefore, the prove is complete.

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2 years ago
Decrease £110 by 50%
stellarik [79]
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What's the lateral area of the following cone?​
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Answer:

Since the base of a cone is a circle, we substitute 2πr for p and πr2 for B where r is the radius of the base of the cylinder. So, the formula for the lateral surface area of a right cone is L. S. A=πrl , where l is the slant height of the cone .

Step-by-step explanation:

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Decimal Form:

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Step-by-step explanation:

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