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Margaret [11]
3 years ago
13

Which expressions are equivalent to this exponential expression

Mathematics
1 answer:
stiks02 [169]3 years ago
8 0

Answer:

c&b

5 {}^{(2 \times  (- 3 ))+ 4 + 4}

5^2

=25

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Find cscθ.<br><br>pls answer
ExtremeBDS [4]

Answer:

The answer to your question is csc Ф = \frac{-5}{4}

Step-by-step explanation:

Process

1.- Determine the sign

We must determine csc Ф in the forth quadrangle, here csc is negative.

2.- Determine the hypotenuse

     c² = a² + b²

     c² = 3² + (-4)²

     c² = 9 + 16

     c² = 25

     c = 5

3.- Determine csc Ф

    csc Ф = \frac{hypotenuse}{opposite side}

    csc Ф = \frac{5}{-4}  = \frac{-5}{4}

7 0
3 years ago
What is the exact number of 2000
GaryK [48]
If you are rounding it will be the same thing
5 0
3 years ago
in a certain store, the regular price of a refrigerator is $600. how much money is saved by buying the refrigerator at 20% off t
Advocard [28]
60$. These are my equations :
600 * 0.2 = 120 ; 600 - 120 = 480
Then...
600 * 0.1 = 60 ; 600 - 60 = 540
Which then became....
540 - 480 = 60
6 0
3 years ago
Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0
3 years ago
TIMED***Which equation is represented by the graph below?
Anuta_ua [19.1K]
   
From the graph we observe:  
If x = 0 then y = 1/2    (because  e⁰ = 1)

\displaystyle \bf \\&#10;\Longrightarrow~~\boxed{\bf y =  \frac{1}{2} e^x}



8 0
3 years ago
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