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sergiy2304 [10]
3 years ago
11

Help with question 3

Mathematics
1 answer:
lys-0071 [83]3 years ago
7 0
What are the questions??
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Determine the equation of a circle with a center at (–4, 0) that passes through the point (–2, 1) by following the steps below.
Nikitich [7]

Answer:

C. (x + 4)² + y² = 5

Step-by-step explanation:

i just did it

6 0
3 years ago
Read 2 more answers
In a city the record monthly high temperature for july is 88. The record monthly low temperature is 30.
Zinaida [17]

Answer:

 58 degrees    or   [30, 88]

Step-by-step explanation:

In such a context, the word "range" can have different meanings. On the one hand it is the difference between high and low:

  88 -30 = 58 . . . . range of temperatures

__

On the other hand, it is the interval between (and including) the high and low:

  [30, 88] . . . . temperature range

3 0
3 years ago
Can anybody help me plzzzz
melisa1 [442]
SSS I’m pretty sure . I’m doing the same thing in math rn
3 0
3 years ago
Use your understanding of the unit circle and trigonometric functions to find the values requested.
vfiekz [6]

Answer:

a) For this case we can use the fact that sin (\pi/3) = \frac{\sqrt{3}}{2}

And for this case since we ar einterested on -\frac{\pi}{3} and we know that the if we are below the y axis the sine would be negative then:

sin (-\pi/3) = -\frac{\sqrt{3}}{2}

b) From definition we can use the fact that tan x= \frac{sin x}{cos x} and we got this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}

We can use the notabl angle \pi/4 and we know that :

sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}

Then we know that 5\pi/4 correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1

Step-by-step explanation:

For this case we can use the notable angls given on the picture attached.

Part a

For this case we can use the fact that sin (\pi/3) = \frac{\sqrt{3}}{2}

And for this case since we ar einterested on -\frac{\pi}{3} and we know that the if we are below the y axis the sine would be negative then:

sin (-\pi/3) = -\frac{\sqrt{3}}{2}

Part b

From definition we can use the fact that tan x= \frac{sin x}{cos x} and we got this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}

We can use the notabl angle \pi/4 and we know that :

sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}

Then we know that 5\pi/4 correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1

6 0
3 years ago
If Jane's shirt cost 20$, but she has a 15% off coupon, what is her cost before tax
alina1380 [7]

Answer:

17

Step-by-step explanation:

The discount on the shirt is 15%

Discount = price* discount rate

               = 20 * 15%

               = 20 * .15

                =3

The new price is the previous price minus the discount

new price = 20-3

new price = 17

8 0
3 years ago
Read 2 more answers
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