Answer:
Step-by-step explanation:
First, put -4x+y=7 into y=mx+b format
move -4x to the other side (or add 4x on both sides)
y=4x+7
now, parallel lines have the same slopes, but not the same y intercepts.
So, you already know the slope of your new line
y=4x+b
now we need to find b (y intercept)
take the point (4,-3) and put it into the equation above
-3=4(4)+b
-3=16+b
move 16 to the other side (or subtract 16)
-19=b
therefore the new line will be y=4x-19
Hope this helps!
Answer:
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Step-by-step explanation:
Answer:
m<N = 76°
Step-by-step explanation:
Given:
∆JKL and ∆MNL are isosceles ∆ (isosceles ∆ has 2 equal sides).
m<J = 64° (given)
Required:
m<N
SOLUTION:
m<K = m<J (base angles of an isosceles ∆ are equal)
m<K = 64° (Substitution)
m<K + m<J + m<JLK = 180° (sum of ∆)
64° + 64° + m<JLK = 180° (substitution)
128° + m<JLK = 180°
subtract 128 from each side
m<JLK = 180° - 128°
m<JLK = 52°
In isosceles ∆MNL, m<MLN and <M are base angles of the ∆. Therefore, they are of equal measure.
Thus:
m<MLN = m<JKL (vertical angles are congruent)
m<MLN = 52°
m<M = m<MLN (base angles of isosceles ∆MNL)
m<M = 52° (substitution)
m<N + m<M° + m<MLN = 180° (Sum of ∆)
m<N + 52° + 52° = 180° (Substitution)
m<N + 104° = 180°
subtract 104 from each side
m<N = 180° - 104°
m<N = 76°
