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3 years ago

3. If a customer has $50.00 to spend, for how many hours can they rent the bicycle?

Mathematics

1 answer:

olya-2409 [2.1K]3 years ago

7 0

Answer:

4 hours

Step-by-step explanation:

Alright, so Steve has $50 in his pocket. He wants to rent a bike for the maximum amount of time possible with his money. It costs him $12 per hour to rent a bike.

To solve this problem use simple arithmetic:

($50/$12=4.16)

So Steve is able to rent the bike for 4.16 hours, but we aren't done yet. Steve cannot purchase 16% of an hour, he can only buy FULL hours, so with his $50 , the maximum amount of time he can buy is 4 hours!

Let me know if you need any further explanations :)

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2 years ago

Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.

Maru [420]

Answer:

$9\text{ln}|x|+2\sqrt{x}+x+C$

Step-by-step explanation:

We have been an integral $\int \frac{9+\sqrt{x}+x}{x}dx$ . We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

$\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx$

$\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx$

Now, we will apply the sum rule of integrals as:

$\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx$

$9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx$

Using common integral $\int \frac{1}{x}dx=\text{ln}|x|$ , we will get:

$9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx$

Now, we will use power rule of integrals as:

$9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx$

$9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2\sqrt{x}+\int 1dx$

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

$9\text{ln}|x|+2\sqrt{x}+x+C$

Therefore, our required integral would be $9\text{ln}|x|+2\sqrt{x}+x+C$ .

4 0

2 years ago

1. A set of weights includes a 5 lb barbell and 8 pairs of weight plates. Each pair, p,

lidiya [134]

Answer:

5 <= y <= 85

Step-by-step explanation:

Since the lowest weight possible is 5lbs (just the barbell and no weights) the lowest point of the range is 5lbs (the y intercept when x = 0)

The highest weight possible is 85lbs since, there is only 8 pairs of weight plates (8 is the input value) and the pairs each weigh 10lbs (the slope of the graph) + 5lbs from the barbell (y-intercept).

Using the function given, if you input 8 as the x value, you get

85 = 10(8) + 5

So the highest value of the range is 85lbs, therefore the range is 5 <= y <= 85.

6 0

3 years ago

Determine the angle of rotation<br><br> please help and provide explanation.

erastovalidia [21]

Answer:

Rotaded areound the orgin counter clockwise 90 degrees

5 0

3 years ago

What is the equation of the line that has a slope of 5 and passes through the point (4,7)?

Katyanochek1 [597]

Answer:

c. y + 13 = 5x

Step-by-step explanation:

y = 5x + b

7 = 5(4) + b

7 = 20 + b

-13 = b

y = 5x - 13

y + 13 = 5x

6 0

2 years ago

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