Determine the equation of a circle with a center at (–4, 0) that passes through the point (–2, 1) by following the steps below.

Mathematics

2 answers:

Nikitich [7]3 years ago

6 0

Answer:

C. (x + 4)² + y² = 5

Step-by-step explanation:

i just did it

lana [24]3 years ago

5 0

Answer:

Step-by-step explanation:

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Divid 15 into two parts such that the sum of their reciprocal is 3/10

emmasim [6.3K]

Let x and y be the 2 parts of 15 ==> x + y=15 (given)

Reciprocal of x and y ==> 1/x +1/y ==> 1/x + 1/y = 3/10 (given)

Let's solve 1/x + 1/y = 3/10 . Common denominator = 10.x.y (reduce to same denominator)

==> (10y+10x)/10xy = 3xy/10xy ==> 10x+10y =3xy

But x+y = 15 , then 10x+10y =150 ==> 150=3xy and xy = 50

Now we have the sum S of the 2 parts that is S = 15 and
their Product = xy =50
Let's use the quadratic equation for S and P==> X² -SX +P =0
Or X² - 15X + 50=0, Solve for X & you will find:
The 1st part of 15 is 10 & the 2nd part is 5

4 0

3 years ago

Find the equation of the line that contains the point (4, - 2) and is perpendicular to the line y = - 2x + 5.

Licemer1 [7]

<h3>Answer:</h3>

y=1/2x

<h3>Solution:</h3>

The slopes of perpendicular lines are opposite reciprocals of each other.
The simplest way to determine a number's reciprocal is to flip it over, like so:
$-2 ~ - > -\displaystyle\frac{1}{2}$
Now, change the sign:
$\displaystyle\frac{1}{2}$
So we have the <em>slope </em>of the line that's <em>perpendicular </em>to the given line.
Now, let's find the line's equation.
First, let's write it in Point-Slope Form:
y-y1=m(x-x1)
y-(-2)=1/2(x-4)
y+2=1/2x-2 (Point slope)
Now, convert to slope-intercept:
y=1/2x+2-2
y=1/2x