Question

5. Segment RT has the endpoints (–3, 4) and (5, –2). What is its midpoint?

Answer 1

Midpoint formula $\left( \dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

Let S denote the midpoint of R and T
$S=\left( \dfrac{-3+5}{2},\dfrac{4-2}{2}\right)\\ S=\left( \dfrac{2}{2},\dfrac{2}{2}\right)\\ S=\left( 1,1\right)$

Answer 2

The coordinates of the midpoint:
$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$
(x₁,y₁) and (x₂,y₂) - the coordinates of the endpoints

$(-3,4) \\ x_1=-3 \\ y_1=4 \\ \\ (5,-2) \\ x_2=5 \\ y_2=-2 \\ \\ \frac{x_1+x_2}{2}=\frac{-3+5}{2}=\frac{2}{2}=1 \\ \\ \frac{y_1+y_2}{2}=\frac{4-2}{2}=\frac{2}{2}=1$

The coordinates of the midpoint are (1,1).