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Ymorist [56]
3 years ago
10

Find the area of a triangle b=72.5 a=105 c=64

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
7 0
There are two methods I know. hope it'd help :)

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Sandy decides to try golfing. She stands on the outer edge of a circular putting green. In the very centre if this putting green
Vedmedyk [2.9K]
Sandy is boring. She should hit the ball towards the hole and hope she doesn't miss.
7 0
3 years ago
The magnitude, M, of an earthquake is defined to be M = log StartFraction I Over S EndFraction, where I is the intensity of the
uranmaximum [27]

The equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is \rm M = log\left ( \dfrac{10S}{S}\right ).

Given

The magnitude, M, of an earthquake is defined to be M = log StartFraction I Over S EndFraction, where I is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and S is the intensity of a "standard" earthquake, which is barely detectable.

<h3>The magnitude of an earthquake</h3>

The magnitude of an earthquake is a measure of the energy it releases.

For an earthquake with 1,000 times more intense than a standard earthquake.

The equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is;

\rm M =log \dfrac{I}{S}\\\\M = log \dfrac{10s}{s}\\\\M=log 10\\\\M =1

Hence, the equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is \rm M = log\left ( \dfrac{10S}{S}\right ).

To know more about the magnitude of earthquakes click the link given below.

brainly.com/question/1337665

5 0
2 years ago
Someone help me please
babymother [125]

You can probably look up a answer key for that worksheet. ;)

6 0
3 years ago
Read 2 more answers
How do I add k to 17-7k​
Annette [7]

Answer:

17-6k

Step-by-step explanation:

-17k+k=6k

4 0
3 years ago
is <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3to%20%5C%3A%20the%20%5C%3A%20power%20%5C%3A%20of%20%5C%3A%20100%7D%7B3to%20%5
Norma-Jean [14]

Remember the laws of exponents:

\frac{a^n}{a^m}=a^{n-m}

Then:

\begin{gathered} \frac{3^{100}}{3^{99}}=3^{100-99} \\ =3^1 \\ =3 \end{gathered}

Therefore:

\frac{3^{100}}{3^{99}}=3

7 0
1 year ago
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