Yes there called stars because when a star in space goes nova it shines in the sky like a little twinkle because it far away the sun is also a star too.<span />
Answer:

Explanation:
From the given information, the LED is operating with a given wavelength of 850 nm or 0.85 μm.
Hence, the material dispersion is 
Now, using the pulse spread formula:


Thus, the pulse spreading as a result of material dispersion is:
Answer:
chris gets 960 and molly gets 1440
Explanation:
add the ratio up and divide
2+3=5
2400/5=480
480x2=960
480x3=1440
960+1440= 2400
Answer:
<em>The correct option is D) fruit</em>
Explanation:
Both the gymnosperm and the angiosperms plants produce seed. Seeds are an essential part of reproduction in plants.
After fertilization has occurred, the ripened ovule is the part which turns into a seed. The size of the seeds depends on the type if plant.
After fertilization, the ovary forms the fruit. As the ovule is present in the ovule hence after fertilization, the seed which was made from the ovule gets enclosed in the fruit which was made from the ovary.
The question is incomplete! The complete question along with answer and explanation is provided below.
Question:
A 0.5 kg mass moves 40 centimeters up the incline shown in the figure below. The vertical height of the incline is 7 centimeters.
What is the change in the potential energy (in Joules) of the mass as it goes up the incline?
If a force of 1.0 N pulled up and parallel to the surface of the incline is required to raise the mass back to the top of the incline, how much work is done by that force?
Given Information:
Mass = m = 0.5 kg
Horizontal distance = d = 40 cm = 0.4 m
Vertical distance = h = 7 cm = 0.07 m
Normal force = Fn = 1 N
Required Information:
Potential energy = PE = ?
Work done = W = ?
Answer:
Potential energy = 0.343 Joules
Work done = 0.39 N.m
Explanation:
The potential energy is given by
PE = mgh
where m is the mass of the object, h is the vertical distance and g is the gravitational acceleration.
PE = 0.5*9.8*0.07
PE = 0.343 Joules
As you can see in the attached image
sinθ = opposite/hypotenuse
sinθ = 0.07/0.4
θ = sin⁻¹(0.07/0.4)
θ = 10.078°
The horizontal component of the normal force is given by
Fx = Fncos(θ)
Fx = 1*cos(10.078)
Fx = 0.984 N
Work done is given by
W = Fxd
where d is the horizontal distance
W = 0.984*0.4
W = 0.39 N.m