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2 years ago

12

Can someone help me?

1 answer:

Alik [6]2 years ago

6 0

Answer:

Resultant = 3.05N

Explanation:

$r = \sqrt{{5}^{2} + 5^{2} - 2(5)(5) \cos(120) }$

$r = \sqrt{25 + 25 - 50(0.8142)}$

$r = \sqrt{50 - 40.71} = \sqrt{9.29}$

$r = 3.05$

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aliya0001 [1]

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From Newton`s second law,

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Therefore, impulse

$= mg \times \sqrt{\frac{2s}{g} } = m \sqrt{2gs}$

Given, $m = 7.3 kg$ and $s = 2.0 m$

Substituting these values, we get

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$= 7.3 \ kg \sqrt{2 \times 9.8 \ m/s^2 \times 2.0 \ m } = 45 .7 \ Ns$ .

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2 years ago

A box slides down a 31° ramp with an acceleration of 0.99 m/s2. Determine the coefficient of kinetic friction between the box an

tino4ka555 [31]

Answer: $\mu$ =0.48

Explanation:

Given

inclination $\theta =31^{\circ}$

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$\mu 8.4=4.057$

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sleet_krkn [62]

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Answer:

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3 years ago